• python练习之-计算器


    学习以堆栈模式编写-计算器

    堆栈特点:先进后出,

    如下:

    #!/opt/python3/bin/python3
    # Author: yong
    import re
    
    def is_symbol(element):
        """进行判断,是否为数字,如果匹配是运算符,返回True,否则返回false"""
        res = False
        symbol=['+','-','*','/','(',')']
        if element in symbol:
            res=True
        return res
    
    def proitry(top_sym, wait_sym):
        """优先级比较"""
        level1 = ['+','-']
        level2 = ['*','/']
        level3 = ['(']
        level4 = [')']
        # 运算符栈顶元素为:+或者-
        if top_sym in level1:
            if wait_sym in level2 or wait_sym in level3:
                return '<'
            else:
                return '>'
            # 以上是优化后的
            # if wait_sym in level1:
            #     return '>'
            # elif wait_sym in level2:  # top_sym='-', wait_sym='*'
            #     return '<'  # 无条件如占
            # elif wait_sym in level3:  # top_sym='-', wait_sym='('
            #     return '<'
            # elif wait_sym in level4:  # top_sym='-', wait_sym=')'
            #     return '>'  # 进行运算
            # else:
            #     return '>'
        # 运算符栈顶元素为:*或者/
        elif top_sym in level2:
            if wait_sym in level3:
                return '<'
            else:
                return '>'
            # if wait_sym in level1:  # top_sym='*' wait_sym='+'
            #     return '>'
            # elif wait_sym in level2:  # top_sym='*' wait_sym='*'
            #     return '>'
            # elif wait_sym in level3:  # top_sym='*' wait_sym='('
            #     return '<'
            # elif wait_sym in level4:  # top_sym='*' wait_sym=')'
            #     return '>'
            # else:
            #     return '>'
        # 运算符栈顶元素为:(
        elif top_sym in level3:
            if wait_sym in level4:  # top_sym='(' wait_sym=')',右括弧遇到左括弧,左括弧弹出
                return '='
            else:
                return '<'  # 只要栈顶元素为(,等待入栈的元素都应该无条件入占
    
    def calculate(num1, symbol, num2):
        """实现具体的运算"""
        res = 0
        if symbol == '+':
            res = num1+num2
        elif symbol == '-':
            res = num1 - num2
        elif symbol == '*':
            res = num1 * num2
        elif symbol == '/':
            res = num1 / num2
        # print('from calculate res is [%s|%s|%s] %s' % (num1, symbol, num2, res))
        return res
    
    
    def init_action(expression):
        """运算字符串进行格式化,以列表返回数字和运算符,如:['-1', '+', '2', '-', '3']"""
        expression = re.sub(' ', '',expression) # 去除空格
        init_l = [i for i in re.split('(-d+.*d*)', expression) if i]
        expression_l = []
        while True:
            if len(init_l) == 0:break
            exp=init_l.pop(0)
            if len(expression_l) == 0 and re.search('^-d+.*d*$', exp): # 匹配开头的负数
                expression_l.append(exp)
                continue
            if len(expression_l) > 0:  # 匹配运算字串中的负数
                if re.search('[+-*/(]$',expression_l[-1]):
                    expression_l.append(exp)
                    continue
            new_l = [i for i in re.split('([+-*/()])',exp) if i]  # 对后续的字符串进行切分
            expression_l  += new_l
        return expression_l
    
    def main(expression_1):
        number_stack = []  # 数字栈
        symbol_stack = []   # 运算符栈
        for ele in expression_1:  # 进行迭代
            #####调试#####
            print('-'*20)
            print('数字栈',number_stack)
            print('运算符栈',symbol_stack)
            print('待入栈运算符',ele)
            ################
            ret = is_symbol(ele)
            if not ret:
                # 压入数字栈
                ele = float(ele)
                number_stack.append(ele)
            else:
                # 压入运算符栈
                while True:
                    if len(symbol_stack) == 0:
                        symbol_stack.append(ele)
                        break
                    res = proitry(symbol_stack[-1], ele)
                    if res == '<':
                        symbol_stack.append(ele)
                        break
                    elif res == '=':
                        symbol_stack.pop()
                    elif res == '>':
                        symbol = symbol_stack.pop()
                        num2 = number_stack.pop()
                        num1 = number_stack.pop()
                        number_stack.append(calculate(num1,symbol,num2))
        else: # 循环执行完毕后,会剩最后一个运算,以下执行最后一次运算完成
            symbol = symbol_stack.pop()
            num2 = number_stack.pop()
            num1 = number_stack.pop()
            number_stack.append(calculate(num1, symbol, num2))
        return number_stack,symbol_stack
    
    if __name__ == '__main__':
        expression='1+2+3*4/6'
        expression_1 = init_action(expression)
        number_stack = main(expression_1)
        print('运算最终结果:%s' % number_stack[0][0])
    

      

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  • 原文地址:https://www.cnblogs.com/zy6103/p/9565251.html
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