• CF1101C Division and Union 线段相交问题


    #include<iostream>
    #include<cstdio>
    #include<algorithm>
    #include<cstdlib>
    #include<cstring>
    #include<string>
    #include<cmath>
    #include<map>
    #include<set>
    #include<vector>
    #include<queue>
    #include<bitset>
    #include<ctime>
    #include<deque>
    #include<stack>
    #include<functional>
    #include<sstream>
    //#include<cctype>
    //#pragma GCC optimize(2)
    using namespace std;
    #define maxn 100005
    #define inf 0x7fffffff
    //#define INF 1e18
    #define rdint(x) scanf("%d",&x)
    #define rdllt(x) scanf("%lld",&x)
    #define rdult(x) scanf("%lu",&x)
    #define rdlf(x) scanf("%lf",&x)
    #define rdstr(x) scanf("%s",x)
    typedef long long  ll;
    typedef unsigned long long ull;
    typedef unsigned int U;
    #define ms(x) memset((x),0,sizeof(x))
    const long long int mod = 1e9 + 7;
    #define Mod 1000000000
    #define sq(x) (x)*(x)
    #define eps 1e-4
    typedef pair<int, int> pii;
    #define pi acos(-1.0)
    //const int N = 1005;
    #define REP(i,n) for(int i=0;i<(n);i++)
    typedef pair<int, int> pii;
    inline ll rd() {
        ll x = 0;
        char c = getchar();
        bool f = false;
        while (!isdigit(c)) {
            if (c == '-') f = true;
            c = getchar();
        }
        while (isdigit(c)) {
            x = (x << 1) + (x << 3) + (c ^ 48);
            c = getchar();
        }
        return f ? -x : x;
    }
    
    ll gcd(ll a, ll b) {
        return b == 0 ? a : gcd(b, a%b);
    }
    int sqr(int x) { return x * x; }
    
    
    /*ll ans;
    ll exgcd(ll a, ll b, ll &x, ll &y) {
        if (!b) {
            x = 1; y = 0; return a;
        }
        ans = exgcd(b, a%b, x, y);
        ll t = x; x = y; y = t - a / b * y;
        return ans;
    }
    */
    
    int T;
    int n;
    struct node {
        int l, r;
        bool operator<(const node&rhs)const {
            if (l < rhs.l)return true;
            if (l > rhs.l)return false;
            if (l == rhs.l)return r < rhs.r;
        }
    }line[maxn];
    int l[maxn], r[maxn];
    
    int main() {
        //ios::sync_with_stdio(0);
        rdint(T);
        while (T--) {
            rdint(n);
            for (int i = 1; i <= n; i++) {
                rdint(l[i]); rdint(r[i]);
                line[i].l = l[i]; line[i].r = r[i];
            }
            sort(line + 1, line + 1 + n);
            bool fg = false;
            int R = -1;
            for (int i = 1; i <= n; i++) {
                if (i == 1)R = line[i].r;
                if (line[i].l > R) {
                    fg = true; break;
                }
                else R = max(R, line[i].r);
            }
            if (!fg) {
                cout << -1 << endl;
            }
            else {
                for (int i = 1; i <= n; i++) {
                    if (r[i] <= R) {
                        cout << 1 << ' ';
                    }
                    else cout << 2 << ' ';
                }
                cout << endl;
            }
        }
        return 0;
    }
    
    EPFL - Fighting
  • 相关阅读:
    [leetcode]259. 3Sum Smaller 三数之和小于目标值
    题型总结之K Sum
    [Leetcode]167. Two Sum II
    题型总结之Sliding Window
    [Leetcode]703. Kth Largest Element in a Stream 数据流中的第 K 大元素
    [Leetcode]307. Range Sum Query
    pycharm同一目录下无法import明明已经存在的.py文件
    python高级特性:迭代器与生成器
    self的含义,为什么类调用方法时需要传参数?
    git三:远程仓库GitHub
  • 原文地址:https://www.cnblogs.com/zxyqzy/p/10275723.html
Copyright © 2020-2023  润新知