• Codeforces Round #320 (Div. 2) [Bayan Thanks-Round] C C Problem about Polyline 数学


                                                                           C. A Problem about Polyline
                                                                                   time limit per test
                                                                                    1 second
                                                                                   memory limit per test
                                                                                      256 megabytes
     

    There is a polyline going through points (0, 0) – (x, x) – (2x, 0) – (3x, x) – (4x, 0) – ... - (2kx, 0) – (2kx + x, x) – ....

    We know that the polyline passes through the point (a, b). Find minimum positive value x such that it is true or determine that there is no such x.

    Input

    Only one line containing two positive integers a and b (1 ≤ a, b ≤ 109).

    Output

    Output the only line containing the answer. Your answer will be considered correct if its relative or absolute error doesn't exceed 10 - 9. If there is no such x then output  - 1 as the answer.

    Sample test(s)
    Input
    3 1
    Output
    1.000000000000
    Input
    1 3
    Output
    -1
    Input
    4 1
    Output
    1.250000000000
     
    题解:对于a<b就是-1
           只有两种情况:
               上升段:a-2*ans*m=b;最小的ans是b所以m<=(a-b)/(2*b);可以得到ans的最小值
     
  • 相关阅读:
    软件开发流程
    计算机与生命体的类比
    cnBeta过期评论查看器,再次更新
    用Ruby写的离线浏览代理服务器,重要更新
    计算机编程常用词汇
    网站创意:商品知识库
    Node.JS进行简单新技术分析及环境搭建
    MongoDB (0)写在前面
    基于CXF Java 搭建Web Service (Restful Web Service与基于SOAP的Web Service混合方案)
    MongoDB (5)不仅仅是数据库
  • 原文地址:https://www.cnblogs.com/zxhl/p/4816083.html
Copyright © 2020-2023  润新知