• 【Project Euler 8】Largest product in a series


    题目要求是:

    The four adjacent digits in the 1000-digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832.

    73167176531330624919225119674426574742355349194934
    96983520312774506326239578318016984801869478851843
    85861560789112949495459501737958331952853208805511
    12540698747158523863050715693290963295227443043557
    66896648950445244523161731856403098711121722383113
    62229893423380308135336276614282806444486645238749
    30358907296290491560440772390713810515859307960866
    70172427121883998797908792274921901699720888093776
    65727333001053367881220235421809751254540594752243
    52584907711670556013604839586446706324415722155397
    53697817977846174064955149290862569321978468622482
    83972241375657056057490261407972968652414535100474
    82166370484403199890008895243450658541227588666881
    16427171479924442928230863465674813919123162824586
    17866458359124566529476545682848912883142607690042
    24219022671055626321111109370544217506941658960408
    07198403850962455444362981230987879927244284909188
    84580156166097919133875499200524063689912560717606
    05886116467109405077541002256983155200055935729725
    71636269561882670428252483600823257530420752963450

    Find the thirteen adjacent digits in the 1000-digit number that have the greatest product. What is the value of this product?    

    看到这题目的那一刻,感觉有点棘手,但是仔细分析起来也还好,并不是很难。

    题目给出的序列是一个很规矩的数字组合。我们可以考虑把它存放到等长的二维数组里面,当然也可以直接存放到一位数组。这里我存放到二维数组里面了。

    首先,我先把序列进行简化来说明。假设我有以下序列,并存放到二维数组里面。

    我从上到下依次给每个数组元素进行编号。

    假设我们要找相连的T个数字的乘积最大值,我们可以设置标记从1号位置开始,直到36号位置结束(为什么是36号位置结束呢?这个应该不用解释吧)。当然这里不是每个位置都需要我们处理,稍后我会说我们怎么跳过部分不需要处理的位置。

    但是这里还有一个问题就是:我们使用的是二维数组存放,我们需要把我们的位置编号计算成二维数组的行号和列号。因为是数组是规矩的,所以我们计算起来还是挺方便的。

    假设我们的标记位置为i,数组的二维长度是n(这里是10),则

    行号rowIndex=i/n,而列号columnIndex=i%n;

    好了,下一步我们来说如何跳过某些位置。我们知道0乘以任何数都得0,所以在0的位置以及0前面T-1个位置都是可以不用计算的,可以直接跳过。

    例如:当前位置为i,数字0的位置为j(j-i<T),则下一次开始计算位置应该为j+1。下面是用java写出来的简单代码。

     1 int[][] numbers=new int[][]{
     2            {7,3,1,6,7,1,7,6,5,3,1,3,3,0,6,2,4,9,1,9,2,2,5,1,1,9,6,7,4,4,2,6,5,7,4,7,4,2,3,5,5,3,4,9,1,9,4,9,3,4},
     3            {9,6,9,8,3,5,2,0,3,1,2,7,7,4,5,0,6,3,2,6,2,3,9,5,7,8,3,1,8,0,1,6,9,8,4,8,0,1,8,6,9,4,7,8,8,5,1,8,4,3},
     4            {8,5,8,6,1,5,6,0,7,8,9,1,1,2,9,4,9,4,9,5,4,5,9,5,0,1,7,3,7,9,5,8,3,3,1,9,5,2,8,5,3,2,0,8,8,0,5,5,1,1},
     5            {1,2,5,4,0,6,9,8,7,4,7,1,5,8,5,2,3,8,6,3,0,5,0,7,1,5,6,9,3,2,9,0,9,6,3,2,9,5,2,2,7,4,4,3,0,4,3,5,5,7},
     6            {6,6,8,9,6,6,4,8,9,5,0,4,4,5,2,4,4,5,2,3,1,6,1,7,3,1,8,5,6,4,0,3,0,9,8,7,1,1,1,2,1,7,2,2,3,8,3,1,1,3},
     7            {6,2,2,2,9,8,9,3,4,2,3,3,8,0,3,0,8,1,3,5,3,3,6,2,7,6,6,1,4,2,8,2,8,0,6,4,4,4,4,8,6,6,4,5,2,3,8,7,4,9},
     8            {3,0,3,5,8,9,0,7,2,9,6,2,9,0,4,9,1,5,6,0,4,4,0,7,7,2,3,9,0,7,1,3,8,1,0,5,1,5,8,5,9,3,0,7,9,6,0,8,6,6},
     9            {7,0,1,7,2,4,2,7,1,2,1,8,8,3,9,9,8,7,9,7,9,0,8,7,9,2,2,7,4,9,2,1,9,0,1,6,9,9,7,2,0,8,8,8,0,9,3,7,7,6},
    10            {6,5,7,2,7,3,3,3,0,0,1,0,5,3,3,6,7,8,8,1,2,2,0,2,3,5,4,2,1,8,0,9,7,5,1,2,5,4,5,4,0,5,9,4,7,5,2,2,4,3},
    11            {5,2,5,8,4,9,0,7,7,1,1,6,7,0,5,5,6,0,1,3,6,0,4,8,3,9,5,8,6,4,4,6,7,0,6,3,2,4,4,1,5,7,2,2,1,5,5,3,9,7},
    12            {5,3,6,9,7,8,1,7,9,7,7,8,4,6,1,7,4,0,6,4,9,5,5,1,4,9,2,9,0,8,6,2,5,6,9,3,2,1,9,7,8,4,6,8,6,2,2,4,8,2},
    13            {8,3,9,7,2,2,4,1,3,7,5,6,5,7,0,5,6,0,5,7,4,9,0,2,6,1,4,0,7,9,7,2,9,6,8,6,5,2,4,1,4,5,3,5,1,0,0,4,7,4},
    14            {8,2,1,6,6,3,7,0,4,8,4,4,0,3,1,9,9,8,9,0,0,0,8,8,9,5,2,4,3,4,5,0,6,5,8,5,4,1,2,2,7,5,8,8,6,6,6,8,8,1},
    15            {1,6,4,2,7,1,7,1,4,7,9,9,2,4,4,4,2,9,2,8,2,3,0,8,6,3,4,6,5,6,7,4,8,1,3,9,1,9,1,2,3,1,6,2,8,2,4,5,8,6},
    16            {1,7,8,6,6,4,5,8,3,5,9,1,2,4,5,6,6,5,2,9,4,7,6,5,4,5,6,8,2,8,4,8,9,1,2,8,8,3,1,4,2,6,0,7,6,9,0,0,4,2},
    17            {2,4,2,1,9,0,2,2,6,7,1,0,5,5,6,2,6,3,2,1,1,1,1,1,0,9,3,7,0,5,4,4,2,1,7,5,0,6,9,4,1,6,5,8,9,6,0,4,0,8},
    18            {0,7,1,9,8,4,0,3,8,5,0,9,6,2,4,5,5,4,4,4,3,6,2,9,8,1,2,3,0,9,8,7,8,7,9,9,2,7,2,4,4,2,8,4,9,0,9,1,8,8},
    19            {8,4,5,8,0,1,5,6,1,6,6,0,9,7,9,1,9,1,3,3,8,7,5,4,9,9,2,0,0,5,2,4,0,6,3,6,8,9,9,1,2,5,6,0,7,1,7,6,0,6},
    20            {0,5,8,8,6,1,1,6,4,6,7,1,0,9,4,0,5,0,7,7,5,4,1,0,0,2,2,5,6,9,8,3,1,5,5,2,0,0,0,5,5,9,3,5,7,2,9,7,2,5},
    21            {7,1,6,3,6,2,6,9,5,6,1,8,8,2,6,7,0,4,2,8,2,5,2,4,8,3,6,0,0,8,2,3,2,5,7,5,3,0,4,2,0,7,5,2,9,6,3,4,5,0}
    22        };
    23        int number=13;
    24        int total=numbers.length*numbers[0].length-1; //Total numbers subtract 1
    25        int k=0;
    26        long temp=1;
    27        long result=1;
    28        for(int i=0;i<=(total-number+1);){
    29            
    30            temp=1;
    31            k=i+number-1;
    32            
    33            for(int j=i;j<=k;j++){
    34                int oneIndex= j/numbers[0].length;               
    35                int twoIndex= j%numbers[0].length;
    36                
    37                temp*=numbers[oneIndex][twoIndex];
    38                
    39                if(numbers[oneIndex][twoIndex]==0)
    40                {
    41                    i=j+1;
    42                    break;
    43                }
    44            }
    45            if(temp!=0)
    46            {
    47                if(temp>result)
    48                {
    49                    //System.out.printf("%3d %d
    ",i,temp);
    50                    result=temp;
    51                }
    52                i++;
    53            }
    54        }
    55        
    56        System.out.println(result);
    Project Euler 8
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  • 原文地址:https://www.cnblogs.com/zwffff/p/4998585.html
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