原题地址:https://oj.leetcode.com/problems/path-sum-ii/
题意:
Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.
For example:Given the below binary tree and
sum = 22
,
5 / 4 8 / / 11 13 4 / / 7 2 5 1
return
[ [5,4,11,2], [5,8,4,5] ]
解题思路:这题需要将根到叶子的路径和为sum的路径都枚举出来。一样是使用递归。
代码:
# Definition for a binary tree node # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: # @param root, a tree node # @param sum, an integer # @return a list of lists of integers def pathSum(self, root, sum): def dfs(root, currsum, valuelist): if root.left==None and root.right==None: if currsum==sum: res.append(valuelist) if root.left: dfs(root.left, currsum+root.left.val, valuelist+[root.left.val]) if root.right: dfs(root.right, currsum+root.right.val, valuelist+[root.right.val]) res=[] if root==None: return [] dfs(root, root.val, [root.val]) return res