这一段时间一直都在刷OJ,这里建一个博客合集,用以记录和分享算法学习的进程。
Problem Description
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one integer per line.
Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
Sample Input
1
100
Sample Output
1
5050
CODE
#include <iostream> using namespace std; int main() { int n; while(cin >> n) { int sum = 0; while(n) { sum += n; n--; } cout << sum << endl; cout << endl; } return 0; }