• UVA 10518 How Many Calls?


    题意:一个递推式第n项%b是多少。

    递推式:

    构造矩阵:

    #include<cstdio>
    #include<cstring>
    #include<cmath>
    #include<vector>
    #include<algorithm>
    using namespace std;
    
    long long MOD;
    long long n;
    
    struct Matrix
    {
        long long A[20][20];
        int R, C;
        Matrix operator*(Matrix b);
    };
    
    Matrix X, Y, Z;
    
    Matrix Matrix::operator*(Matrix b)
    {
        Matrix c;
        memset(c.A, 0, sizeof(c.A));
        int i, j, k;
        for (i = 1; i <= R; i++)
        for (j = 1; j <= b.C; j++)
        for (k = 1; k <= C; k++)
            c.A[i][j] = (c.A[i][j] + (A[i][k] * b.A[k][j]) % MOD) % MOD;
        c.R = R; c.C = b.C;
        return c;
    }
    
    void init()
    {
        memset(X.A, 0, sizeof X.A);
        memset(Y.A, 0, sizeof Y.A);
        memset(Z.A, 0, sizeof Z.A);
    
        Z.R = 1; Z.C = 3;
        Z.A[1][1] = Z.A[1][2] = Z.A[1][3] = 1;
    
        X.R = 3; X.C = 3;
        X.A[1][1] = 0; X.A[1][2] = 1; X.A[1][3] = 0;
        X.A[2][1] = 1; X.A[2][2] = 1; X.A[2][3] = 0;
        X.A[3][1] = 0; X.A[3][2] = 1; X.A[3][3] = 1;
    
        Y.R =3; Y.C = 3;
        for (int i = 1; i <= 3; i++) Y.A[i][i] = 1;
    }
    
    void work()
    {
        while (n)
        {
            if (n % 2 == 1) Y = Y*X;
            n = n >> 1;
            X = X*X;
        }
        Z = Z*Y;
    
        printf("%lld
    ", Z.A[1][1]);
    }
    
    int main()
    {
        int Case = 1;
        while (~scanf("%lld%lld", &n, &MOD))
        {
            if (!n&&!MOD) break;
            init();
            printf("Case %d: %lld %lld ", Case++, n, MOD);
            work();
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zufezzt/p/5245161.html
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