程序跳转到itunes商店

找到应用程序，点击应用程序下面的小三角图标，再选择”复制链接“，就可以获取此应用的链接了。

比如：

itunes.apple.com/cn/app/bai-du-wen-kuhd/id483064532?mt=8

然后将 https:// 替换为 itms:// 或者 itms-apps://：

 itms://itunes.apple.com/gb/app/yi-dong-cai-bian/id391945719?mt=8

 itms-apps:// itunes.apple.com/gb/app/yi-dong-cai-bian/id391945719?mt=8  

然后在程序中写如下代码：

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"itms://itunes.apple.com/cn/app/bai-du-wen-kuhd/id483064532?mt=8"]];

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"itunes.apple.com/cn/app/bai-du-wen-kuhd/id483064532?mt=8"]]	

注意：只能在真机上调试出效果，模拟器上无效果。
"Error Domain=WebKitErrorDomain Code=101 The URL can't be shown."
http://stackoverflow.com/questions/4299403/how-to-handle-app-urls-in-a-uiwebview

http://stackoverflow.com/questions/4299403/how-to-handle-app-urls-in-a-uiwebview

- (void)webView:(UIWebView *)wv didFailLoadWithError:(NSError *)error {

    // Give iOS a chance to open it.

    NSURL *url = [NSURL URLWithString:[error.userInfo objectForKey:@"NSErrorFailingURLStringKey"]];

    if ([error.domain isEqual:@"WebKitErrorDomain"]

        && error.code == 101

        && [[UIApplication sharedApplication]canOpenURL:url])

    {

        [[UIApplication sharedApplication]openURL:url];

        return;

    }



    // Normal error handling…
}

- (BOOL)webView:(UIWebView *)wv shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {



    // Determine if we want the system to handle it.

    NSURL *url = request.URL;

    if (![url.scheme isEqual:@"http"] && ![url.scheme isEqual:@"https"]) {

        if ([[UIApplication sharedApplication]canOpenURL:url]) {

            [[UIApplication sharedApplication]openURL:url];

            return NO;

        }

    }

    return YES;

}

- (void)webView:(UIWebView *)wv didFailLoadWithError:(NSError *)error {

    // Ignore NSURLErrorDomain error -999.

    if (error.code == NSURLErrorCancelled) return;



    // Ignore "Fame Load Interrupted" errors. Seen after app store links.

    if (error.code == 102 && [error.domain isEqual:@"WebKitErrorDomain"]) return;



    // Normal error handling…

}

iphone开发笔记和技巧总结(原址持续更新)转载

http://www.cnblogs.com/zhwl/archive/2012/03/09/2387530.html