题解是直接对一维升序排列,然后计算有树状数组中比二维小的点即可
但是对二维降序排列为什么不信呢??
/* */ #include<iostream> #include<cstring> #include<cstdio> #include<algorithm> using namespace std; #define maxn 1010 #define ll long long int n,m,k; ll bit[maxn*maxn]; struct Edge{ int u,v,id; bool operator<(const Edge & a) const{ return v>a.v; } }edge[maxn*maxn]; void add(int x){ while(x<=k){ bit[x]++; x+=x&-x; } } ll query(int x){ ll res=0; while(x){ res+=bit[x]; x-=x&-x; } return res; } int main(){ int t,tt; scanf("%d",&t); for(int tt=1;tt<=t;tt++){ memset(bit,0,sizeof bit); scanf("%d%d%d",&n,&m,&k); for(int i=1;i<=k;i++){ scanf("%d%d",&edge[i].u,&edge[i].v); } sort(edge+1,edge+1+n); ll ans=0; for(int i=1;i<=k;i++){ ans+=query(edge[i].u-1); add(edge[i].u); } printf("Test case %d: %lld ",tt,ans); } return 0; }
ac代码
#include <iostream> #include <cstring> #include <cstdio> #include <algorithm> #define LL long long using namespace std; const int M=1003; LL C[M]; int n,m,k; struct Node { int x,y; }edge[1003*1002]; bool cmp(Node a,Node b) { if(a.x==b.x)return a.y<=b.y; else return a.x<b.x; } int lowbit(int a) { return a&(-a); } void Modify(int p,int c) { for(int i=p;i<=m;i+=lowbit(i)) C[i]+=c; } int getsum(int p) { LL ans=0; for(int i=p;i>0;i-=lowbit(i)) { ans+=C[i]; } return ans; } int main() { int T=0; int cas; scanf("%d",&cas); while(cas--) { scanf("%d%d%d",&n,&m,&k); for(int i=0;i<k;i++) scanf("%d%d",&edge[i].x,&edge[i].y); memset(C,0,sizeof(C)); sort(edge,edge+k,cmp); LL ans=0; for(int i=0;i<k;i++) { Modify(edge[i].y,1); ans+=(getsum(m)-getsum(edge[i].y)); } T++; printf("Test case %d: %lld ",T,ans); } return 0; }