• 哈理工多校算法赛五


    A 逆序数:https://www.nowcoder.com/acm/contest/77/A

    #include <bits/stdc++.h>
    using namespace std;
    int main()
    {
        int n;
        while(~scanf("%d",&n)&&n)
        {
            int arr[n+5],maxa=0,sign[100005],cnt[100005];
            long long sum=0;
            memset(sign,0,sizeof(sign));
            memset(cnt,0,sizeof(cnt));
            for(int i=1;i<=n;i++)
            {
                scanf("%d",&arr[i]);
                maxa=max(maxa,arr[i]);
                sign[arr[i]]++;
                for(int j=arr[i]+1;j<=maxa;j++)
                    cnt[arr[i]]+=sign[j];
            }
            for(int i=0;i<=maxa;i++)
                sum+=cnt[i];
            printf("%lld
    ",sum);
        }
     
        return 0;
    }
    View Code

    同一个思路 别人的代码真是精简

    #include <bits/stdc++.h>
    using namespace std;
    int main()
    {
        int n,k; scanf("%d",&n);
        long long sum=0;
        int a[100005];
        memset(a,0,sizeof(a));
        while(n--)
        {
            scanf("%d",&k);
            sum+=a[k];
            for(int i=0;i<k;i++)
                a[i]++;
        }
        printf("%lld
    ",sum);
    
        return 0;
    }
    View Code

    B Big Water Problem:https://www.nowcoder.com/acm/contest/77/B

    #include <bits/stdc++.h>
    using namespace std;
    int main()
    {
        int n,m;
        while(~scanf("%d%d",&n,&m)&&n&&m)
        {
            long long b[n+5],num;
            memset(b,0,sizeof(b));
            for(int i=1;i<=n;i++)
            {
                scanf("%lld",&num);
                if(i==1) b[i]=num;
                else b[i]=b[i-1]+num;
            }
            while(m--)
            {
                int sel,x,y;
                scanf("%d%d%d",&sel,&x,&y);
                if(sel==1)
                {
                    for(int i=x;i<=n;i++) 
                        b[i]+=y;
                }
                else printf("%lld
    ",b[y]-b[x-1]);
            }
        }
     
        return 0;
    }
    View Code

    C 字符串的问题:https://www.nowcoder.com/acm/contest/77/C

    #include <bits/stdc++.h>
    using namespace std;
    char ch[1000005],ans[1000005],lans[1000005];
    int flag,lch;
    void midjudge(int len)
    {
        int k=0,j;
        for(j=1;j<lch-1;j++)
        {
            if(ch[j]==ans[k]) k++;
            else k=0;
            if(k==len+1) break;
        }
        if(j<lch-1)
        {
            strcpy(lans,ans);
            flag=1;
        }
        return ;
    }
    void judge(int len)
    {
        int k=0,j;
        for(j=lch-1-len;j<lch;j++)
            if(ans[k++]==ch[j]) continue;
        if(j==lch) midjudge(len);
        return ;
    }
    int main()
    {
        while(gets(ch))
        {
            memset(ans,0,sizeof(ans));
            flag=0,lch=strlen(ch);
            int j=0;
            for(int i=0;i<lch-1;i++)
            {
                ans[j++]=ch[i];
                if(ch[i]==ch[lch-1]) judge(i);
            }
            if(flag) puts(lans);
            else printf("Just a legend
    ");
        }
      
        return 0;
    }
    View Code

    D 集合问题:https://www.nowcoder.com/acm/contest/77/D

    #include<bits/stdc++.h>
    using namespace std;
    int a,b,n,ans[100005],p[100005];
    map<int,int>m;
    bool dfs(int num,int c)
    {
        if(c==2)
        {
            if(ans[m[b-num]]==-1)
            {
                ans[m[b-num]]=ans[m[num]]=1;
                return 1;
            }
            if(ans[m[a-num]]==-1)
            {
                ans[m[a-num]]=ans[m[num]]=0;
                return 1;
            }
            if(ans[m[a-num]]==1)
            {
                ans[m[a-num]]=ans[m[num]]=0;
                return dfs(b-a+num,1);
            }
            return 0;
        }
        else
        {
            if(ans[m[a-num]]==-1 || ans[m[a-num]]==0)
            {
                ans[m[a-num]]=ans[m[num]]=0;
                return 1;
            }
            if(ans[m[a-num]]==1)
            {
                ans[m[a-num]]=ans[m[num]]=0;
                return dfs(b-a+num,1);
            }
            return 0;
        }
    }
    int main()
    {
            scanf("%d%d%d",&n,&a,&b);
            for(int i=1;i<=n;i++)
            {
                scanf("%d",&p[i]);
                m[p[i]]=i;
                ans[i]=-1;
            }
            for(int i=1;i<=n;i++)
                if(ans[i]==-1)
                {
                    if(dfs(p[i],2));
                    else { printf("NO
    "); return 0;}
                }
            printf("YES
    ");
            for(int i=1;i<n;i++)
                printf("%d ",ans[i]);
            printf("%d
    ",ans[n]);
         
        return 0;
    }
    View Code

    E 情人节的灯泡:https://www.nowcoder.com/acm/contest/77/E

    #include <bits/stdc++.h>
    int main()
    {
        int n,m;
        while(~scanf("%d%d",&n,&m)&&n&&m)
        {
            int arr[n+5][n+5],sel;
            for(int i=1;i<=n;i++)
                for(int j=1;j<=n;j++)
                    scanf("%d",&arr[i][j]);
            while(m--)
            {
                scanf("%d",&sel);
                if(sel==1)
                {
                    int x,y; scanf("%d%d",&x,&y);
                    arr[x][y]= arr[x][y] ? 0:1 ;
                }
                else
                {
                    int x1,y1,x2,y2,sum=0;
                    scanf("%d%d%d%d",&x1,&y1,&x2,&y2);
                    for(int i=x1;i<=x2;i++)
                        for(int j=y1;j<=y2;j++)
                            sum+=arr[i][j];
                    printf("%d
    ",sum);
                }
            }
        }
     
        return 0;
    }
    View Code

    F The Biggest Water Problem:https://www.nowcoder.com/acm/contest/77/F

    #include <bits/stdc++.h>
    using namespace std;
    int main()
    {
        long long n;
        while(~scanf("%lld",&n)&&n>0)
        {
            long long ans=0;
            while(n>9)
            {
                ans=0;
                while(n)
                {
                    ans+=n%10;
                    n/=10;
                }
                n=ans;
            }
            printf("%lld
    ",ans);
        }
     
        return 0;
    }
    View Code

    G 送分啦-QAQ:https://www.nowcoder.com/acm/contest/77/G

    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
        long long n,i,j;
        long long a[1005];
        a[1]=1,a[2]=2;
        for(i=3;;i++)
        {
            a[i]=a[i-1]+a[i-2];
            if(a[i]>1e9) break;
        }
        while(scanf("%lld",&n)!=EOF)
        {
            for(j=1;j<=i;j++)
                if(a[j]>=n) break;
            if(a[j]==n) printf("Sha
    ");
            else printf("Xian
    ");
        }
        return 0;
    }
    View Code

    H Tree Recovery:https://www.nowcoder.com/acm/contest/77/H

    #include <bits/stdc++.h>
    using namespace std;
    int n,m;
    long long arr[100005];
    void opsC()
    {
        int a,b,c;
        scanf("%d%d%d",&a,&b,&c);
        for(int i=a;i<=b;i++)
            arr[i]+=c;
    }
    void opsQ()
    {
        int a,b;
        long long ans=0;
        scanf("%d%d",&a,&b);
        for(int i=a;i<=b;i++)
            ans+=arr[i];
        printf("%lld
    ",ans);
    }
    int main()
    {
        while(~scanf("%d%d",&n,&m)&&n&&m)
        {
            memset(arr,0,sizeof(arr));
            for(int i=1;i<=n;i++) scanf("%lld",&arr[i]);
            while(m--)
            {
                char sel; getchar();
                scanf("%c",&sel);
                if(sel=='Q') opsQ();
                else opsC();
            }
        }
     
        return 0;
    }
    View Code
  • 相关阅读:
    kafka中配置细节
    kafka原理
    storm中的基本概念
    Spring装配Bean的过程补充
    Spring装配Bean的过程
    java中被遗忘的native关键字
    水塘抽样
    js常用总结
    HttpServletResponse status对应的状态信息
    mongoDB常用命令总结
  • 原文地址:https://www.cnblogs.com/zquzjx/p/8585789.html
Copyright © 2020-2023  润新知