HDU 2123 An easy problem

http://acm.hdu.edu.cn/showproblem.php?pid=2123

Problem Description

In this problem you need to make a multiply table of N * N ,just like the sample out. The element in the i^th row and j^th column should be the product(乘积) of i and j.

 

Input

The first line of input is an integer C which indicate the number of test cases.

Then C test cases follow.Each test case contains an integer N (1<=N<=9) in a line which mentioned above.

 

Output

For each test case, print out the multiply table.

 

Sample Input

2

1

4

 

Sample Output

1

1 2 3 4

2 4 6 8

3 6 9 12

4 8 12 16

代码：

#include <bits/stdc++.h>
using namespace std;

int num[10][10];

int main() {
    int T;
    scanf("%d", &T);
    while(T --) {
        int x;
        scanf("%d", &x);

        for(int i = 1; i <= x; i ++) {
            for(int j = 1; j <= x; j ++)
                num[i][j] = i * j;
        }

        for(int i = 1; i <= x; i ++) {
            for(int j = 1; j <= x; j ++) {
                if(j != x)
                    printf("%d ", num[i][j]);
                else
                    printf("%d
", num[i][j]);
            }
        }

    }
    return 0;
}