• #Leetcode# 257. Binary Tree Paths


    https://leetcode.com/problems/binary-tree-paths/

    Given a binary tree, return all root-to-leaf paths.

    Note: A leaf is a node with no children.

    Example:

    Input:
    
       1
     /   
    2     3
     
      5
    
    Output: ["1->2->5", "1->3"]
    
    Explanation: All root-to-leaf paths are: 1->2->5, 1->3

    代码:

    /**
     * Definition for a binary tree node.
     * struct TreeNode {
     *     int val;
     *     TreeNode *left;
     *     TreeNode *right;
     *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
     * };
     */
    class Solution {
    public:
        vector<string> binaryTreePaths(TreeNode* root) {
            vector<string> ans;
            A(ans, "", root);
            return ans;
        }
        void A(vector<string>& ans, string res, TreeNode* root) {
            if(root) {
                res += to_string(root -> val);
                if(root -> left)
                    A(ans, res + "->", root -> left);
                if(root -> right)
                    A(ans, res + "->", root -> right);
                if(root -> left == NULL && root -> right == NULL)
                    ans.push_back(res);
            }
        }
    };
    

      

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  • 原文地址:https://www.cnblogs.com/zlrrrr/p/10117930.html
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