• 1147 Heaps (30 分)


    1147 Heaps (30 分)
     

    In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))

    Your job is to tell if a given complete binary tree is a heap.

    Input Specification:

    Each input file contains one test case. For each case, the first line gives two positive integers: M (≤ 100), the number of trees to be tested; and N (1 < N ≤ 1,000), the number of keys in each tree, respectively. Then M lines follow, each contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.

    Output Specification:

    For each given tree, print in a line Max Heap if it is a max heap, or Min Heap for a min heap, or Not Heap if it is not a heap at all. Then in the next line print the tree's postorder traversal sequence. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line.

    Sample Input:

    3 8
    98 72 86 60 65 12 23 50
    8 38 25 58 52 82 70 60
    10 28 15 12 34 9 8 56
    

    Sample Output:

    Max Heap
    50 60 65 72 12 23 86 98
    Min Heap
    60 58 52 38 82 70 25 8
    Not Heap
    56 12 34 28 9 8 15 10
    
     
     
    依然是堆的性质,再加一个后序遍历,这题30分有点多
     
     1 #include <bits/stdc++.h>
     2 
     3 using namespace std;
     4 int an[1005];
     5 int n,m;
     6 vector<int> v;
     7 
     8 void predfs(int x){
     9     if(x*2 <= m)
    10         predfs(x*2);
    11     if(x*2+1 <= m)
    12         predfs(x*2+1);
    13     v.push_back(an[x]);
    14 }
    15 
    16 int main(){
    17     cin >> n >> m;
    18     while(n--){
    19         v.clear();
    20         bool isbig = true, islittle = true;
    21         for(int i = 1 ; i <= m ; ++i){
    22             cin >> an[i];
    23             if(i > 2){
    24                 if(an[i/2] < an[i]) isbig = false;
    25                 if(an[i/2] > an[i]) islittle = false;
    26             }
    27         }
    28         if(isbig)
    29             puts("Max Heap");
    30         else if(islittle)
    31             puts("Min Heap");
    32         else
    33             puts("Not Heap");
    34         predfs(1);
    35         for(int i = 0 ; i < v.size(); ++i)
    36             printf("%d%c",v[i], i == v.size()-1? '
    ':' ');
    37     }
    38 
    39     return 0;
    40 }
     
     
     
     
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  • 原文地址:https://www.cnblogs.com/zllwxm123/p/11273937.html
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