Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[ [2], [3,4], [6,5,7], [4,1,8,3] ]
The minimum path sum from top to bottom is 11
(i.e., 2 + 3 + 5 + 1 = 11).
Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.
从下往上
// Find the lesser of its two children, and sum the current value in the triangle with it
1 class Solution: 2 def minimumTotal(self, a): 3 """ 4 :type triangle: List[List[int]] 5 :rtype: int 6 """ 7 n = len(a) 8 dp = a[n-1] 9 for layer in range(0,n-1)[::-1]: 10 for i in range(layer+1): 11 dp[i] = min(dp[i],dp[i+1]) + a[layer][i] 12 return dp[0]