| Three Families |
Three families share a garden. They usually clean the garden together at the end of each week, but last week, family C was on holiday, so family A spent 5 hours, family B spent 4 hours and had everything done. After coming back, family C is willing to pay $90 to the other two families. How much should family A get? You may assume both families were cleaning at the same speed.
$90/(5+4)*5=$50? No no no. Think hard. The correct answer is $60. When you figured out why, answer the following question: If family A and B spent x and y hours respectively, and family C paid $z, how much should family A get? It is guaranteed that both families should get non-negative integer dollars.
WARNING: Try to avoid floating-point numbers. If you really need to, be careful!
Input
The first line contains an integer T ( T
100), the number of test cases. Each test case contains three integers x, y, z ( 1x, y10, 1z1000).
Output
For each test case, print an integer, representing the amount of dollars that family A should get.
Sample Input
2 5 4 90 8 4 123
Sample Output
60 123
题目大意：水题，不解释。推出计算公式瞬秒！
1 #include<iostream> 2 #include<cstdio> 3 using namespace std; 4 int main(){ 5 int T;cin>>T; 6 while(T--){ 7 int x,y,z; 8 cin>>x>>y>>z; 9 cout<<(3*x*z)/(x+y)-z<<' '; 10 }return 0; 11 }