• 10.22 比赛总结 修剪草坪(mowlawn)、玉米迷宫(cornmaze)


    地址:http://pan.baidu.com/s/1hq03BIO

    T1:之前想错了= =  f[i]表示前i位,且第i位不选的最小价值   f[i]=min{f[j]+A[i]} ,那么ans=TOT-f[i] n-k<i<n

          正着想f[i]=max{f[j-1]+sum[i]-sum[j],f[i-1]}也可以用单调队列维护

    #include<set>
    #include<map>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<iostream>
    #include<algorithm>
    using namespace std;
    const int N = 100010;
    typedef long long lld;
    #define inf 2147483647777777
    #define For(i,n) for(int i=1;i<=n;i++)
    #define Rep(i,l,r) for(int i=l;i<=r;i++)
    using namespace std;
    
    void read(int &v){
        char ch=getchar();int num=0;
        while(ch<'0'||ch>'9') ch=getchar();
        while(ch>='0'&&ch<='9') {
            num=num*10+ch-'0';
            ch=getchar();
        }
        v=num;
    }
    
    int n,k,l,r;
    lld TOT,ans=inf,f[N];
    int A[N];
    struct queues{
        int id;lld v;
    }q[N];
    
    void init(){
        read(n);read(k);
        For(i,n) read(A[i]),TOT+=A[i];
    }
    
    void dp(){
        For(i,n){
            f[i]=A[i]+q[l].v;
            while(q[r].v>f[i]&&l<=r) r--;
            q[++r].v=f[i];q[r].id=i;
            while(q[l].id<i-k) l++;
        }
        Rep(i,n-k,n) ans=min(ans,f[i]);
        printf("%I64d",TOT-ans);
    }
    
    int main(){
        freopen("mowlawn.in","r",stdin);
        freopen("mowlawn.out","w",stdout);
        init();
        dp();
        return 0;
    }
    T1

     堆版本的,应老师要求写的= =

    #include<set>
    #include<map>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring>
    #include<iostream>
    #include<algorithm>
    using namespace std;
    const int N = 100010;
    typedef long long lld;
    typedef pair<lld,int> point;
    #define w first
    #define id second
    #define For(i,n) for(int i=1;i<=n;i++)
    #define Rep(i,l,r) for(int i=l;i<=r;i++)
    
    point H[N];
    lld ans,TOT;
    int L,Loc[N],n,k,A[N];
    lld dp[N];
    
    //下调
    void Down(int No,point H[]){
        int fa=No,son=No*2;
        while(son<=L){
            if(H[son].w>H[son+1].w&&son<L) {
                //swap(Loc[H[son].id],Loc[H[son+1].id]);
                son++;
            }
            if(H[son].w<H[fa].w) {
                swap(Loc[H[son].id],Loc[H[fa].id]);
                point c=H[son];H[son]=H[fa];H[fa]=c;
            }
            fa=son;son=fa*2;
        }
    }
    //删除堆元素
    void Delete(int No,point H[]){
        Loc[H[L].id]=Loc[H[No].id];
        H[No]=H[L--];
        Down(No,H);
    }
    
    //上调 
    void Up(int No,point H[]){
        int fa=L/2,son=L;
        while(H[son].w<H[fa].w&&son>1){
            swap(Loc[H[son].id],Loc[H[fa].id]);
            point c=H[son];H[son]=H[fa];H[fa]=c;
            son=fa;fa=son/2;
        }
    }
    
    void Insert(point NODE,point H[]){
        H[++L]=NODE;
        Loc[NODE.id]=L;
        Up(L,H);
    }
    
    void init(){
        scanf("%d%d",&n,&k);
        For(i,n) scanf("%d",&A[i]),TOT+=A[i];
    }
    
    void DP(){
        ans=1e18;
        Insert(make_pair(0,0),H);
        For(i,n){
            dp[i]=H[1].w+A[i];
            Insert(make_pair(dp[i],i),H);
            if(i>k)  Delete(Loc[i-k-1],H);
        }
        For(i,n) cout<<dp[i]<<endl;
        Rep(i,n-k,n) ans=(dp[i]<ans)?(dp[i]):(ans);
        printf("%I64d
    ",TOT-ans);
    }
    
    int main(){
        freopen("mowlawn.in","r",stdin);
        freopen("mowlawn.out","w",stdout);
        init();
        DP();
        return 0;
    }
    

    T2: 很坑爹的bfs,考场上没看到是一些传送门。。就写了一个传送门的。。。由于增量是1,所以可以不用bfs

     1 #include<set>
     2 #include<map>
     3 #include<cstdio>
     4 #include<cstdlib>
     5 #include<cstring>
     6 #include<iostream>
     7 #include<algorithm>
     8 using namespace std;
     9 const int N = 310;
    10 const int dx[5]={0,-1,1,0,0},
    11           dy[5]={0,0,0,-1,1};
    12 typedef pair<pair<int,int>,int>  newp;
    13 #define x first
    14 #define y second
    15 #define For(i,n) for(int i=1;i<=n;i++)
    16 #define Rep(i,l,r) for(int i=l;i<=r;i++)
    17 char maze[N][N];
    18 int x,y,n,m;bool hash[N][N];
    19 newp q[N*3*N];
    20 pair<int,int> two[3],cnt[30][2];
    21 
    22 void init(){
    23     scanf("%d%d",&n,&m);
    24     For(i,n) {
    25         scanf("%s",maze[i]+1);
    26         For(j,m){
    27             if(maze[i][j]=='@'){x=i;y=j;}
    28             if(isupper(maze[i][j])) 
    29                 if(cnt[maze[i][j]-'A'+1][0].first>0)   cnt[maze[i][j]-'A'+1][1]=make_pair(i,j);
    30                 else                                   cnt[maze[i][j]-'A'+1][0]=make_pair(i,j);
    31         }
    32     }
    33 }
    34 
    35 int BFS(){
    36     int l=0,r=1;q[r]=make_pair(make_pair(x,y),0);hash[x][y]=true;
    37     while(l<r){
    38         newp head=q[++l];
    39         pair<int,int> First=head.x;int w=head.y;
    40         if(maze[First.x][First.y]=='=') return w;
    41         For(i,4){
    42             int tx=First.x+dx[i],ty=First.y+dy[i];
    43             if(tx>n||ty>m||tx<=0||ty<=0) continue;
    44             if(!hash[tx][ty]&&maze[tx][ty]!='#'){
    45                 hash[tx][ty]=true;
    46                 if(isupper(maze[tx][ty])){
    47                       if(cnt[maze[tx][ty]-'A'+1][0]!=make_pair(tx,ty)){
    48                           q[++r]=make_pair(cnt[maze[tx][ty]-'A'+1][0],w+1);
    49                           hash[tx][ty]=false;
    50                       }
    51                       else{
    52                           q[++r]=make_pair(cnt[maze[tx][ty]-'A'+1][1],w+1);
    53                           hash[tx][ty]=false;
    54                       }
    55                     continue;
    56                 }
    57                 q[++r]=make_pair(make_pair(tx,ty),w+1);
    58             }
    59         }
    60     }
    61 }
    62 
    63 int main(){
    64     freopen("cornmaze.in","r",stdin);
    65     freopen("cornmaze.out","w",stdout);
    66     init();
    67     printf("%d
    ",BFS());
    68     return 0;
    69 }
    T2
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  • 原文地址:https://www.cnblogs.com/zjdx1998/p/4044328.html
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