• Transaction rolled back because it has been marked as rollback-only


    嵌套事务异常Transaction rolled back because it has been marked as rollback-only导致的原因和处理方法

    参考:https://fangshixiang.blog.csdn.net/article/details/80445912?utm_medium=distribute.pc_relevant.none-task-blog-searchFromBaidu-2.not_use_machine_learn_pai&depth_1-utm_source=distribute.pc_relevant.none-task-blog-searchFromBaidu-2.not_use_machine_learn_pai

    根本原因:手动捕捉了事务中的异常导致事务失效,提交已经标记必须回滚的事务

    例如:

    @Transactional
    public void testA(){
        mapper.insert(...)
        try{
            testB();
        }catch(Exception e){
          e.printStackTrace();
        }
    }
    @Transactional
    public void testB(){
          int a = 1/0;  
    }

    testA和testB都需要事务,事务传播属性默认为REQUIRED,调用testA时,创建新事务,调用testB时已经有事务了,则加入testA的事务,当发生异常时,拦截器拦截到testB异常,将共同的事务标记为rollback-only

    testA方法中由于使用了try catch,导致事务失效,截器无法捕捉到异常,testA正常提交,提交时发现事务已经被标记成rollback-only了,所以会抛出Transaction rolled back because it has been marked as rollback-only

    解决办法:

    1. 不要在事务控制的方法中手动try catch 捕捉异常

    2. 在try catch中捕捉到异常后继续抛出,让拦截器拦截到

    2.在catch中手动回滚 TransactionAspectSupport.currentTransactionStatus().setRollbackOnly(); //手动设置回滚

    @Transactional
    public void testA(){
        mapper.insert(...)
        try{
            testB();
        }catch(Exception e){
          e.printStackTrace();
    // 以下方法二选一
    //1. 设置手动回滚 TransactionAspectSupport.currentTransactionStatus() .setRollbackOnly();
    //2. 继续往外抛出异常
    throw new RuntimeException(e.toString); } } @Transactional
    public void testB(){ int a = 1/0; }

     

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  • 原文地址:https://www.cnblogs.com/zincredible/p/14170703.html
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