• BZOJ 2756 奇怪的游戏


    1.二分+网络流+各种判。

    2.网上很多程序都是错的。

    3.一个%lld打成%d调了一年。

    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<queue>
    #include<algorithm>
    #define maxn 45
    #define maxv 1700
    #define maxe 1000500
    #define inf (1LL<<50)
    using namespace std;
    long long tt,n,m,map[maxn][maxn],col[maxn][maxn],n1=0,n2=0,s1=0,s2=0,mx=0;
    long long dx[]={0,0,1,0,-1},dy[]={0,1,0,-1,0};
    long long dis[maxv],nume=1,g[maxv],s,t;
    queue <long long> q;
    bool vis[maxv];
    struct edge
    {
        long long v,f,nxt;
    }e[maxe];
    long long p(long long x,long long y)
    {
        return (x-1)*m+y;
    }
    void addedge(long long u,long long v,long long f)
    {
        e[++nume].v=v;e[nume].f=f;e[nume].nxt=g[u];g[u]=nume;
        e[++nume].v=u;e[nume].f=0;e[nume].nxt=g[v];g[v]=nume;
    }
    bool checks(long long x,long long y)
    {
        if ((x>=1) && (x<=n) && (y>=1) && (y<=m)) return true;
        return false;
    }
    void build(long long x)
    {
        nume=1;memset(g,0,sizeof(g));
        s=0;t=n1+n2+1;
        for (long long i=1;i<=n;i++) 
            for (long long j=1;j<=m;j++)
            {
                long long now=p(i,j);
                if (col[i][j]) addedge(s,now,x-map[i][j]);
                else addedge(now,t,x-map[i][j]);
                if (col[i][j])
                {
                    for (long long k=1;k<=4;k++)
                    {
                        long long a=i+dx[k],b=j+dy[k],ret=p(a,b);
                        if (checks(a,b)) addedge(now,ret,inf);
                    }
                }
            }
    }
    bool bfs()
    {
        for (long long i=s;i<=t;i++) {dis[i]=inf;vis[i]=false;}
        q.push(s);dis[s]=0;vis[s]=true;
        while (!q.empty())
        {
            long long head=q.front();q.pop();
            for (long long i=g[head];i;i=e[i].nxt)
            {
                long long v=e[i].v;
                if ((e[i].f) && (dis[v]>dis[head]+1))
                {
                    dis[v]=dis[head]+1;
                    if (!vis[v]) {q.push(v);vis[v]=true;}
                }
            }
        }
        if (dis[t]==inf) return false;
        return true;
    }
    long long dinic(long long x,long long low)
    {
        if (x==t) return low;
        long long ret=0;
        for (long long i=g[x];i && low;i=e[i].nxt)
        {
            long long v=e[i].v;
            if ((e[i].f) && (dis[v]==dis[x]+1))
            {
                long long dd=dinic(v,min(e[i].f,low));
                e[i].f-=dd;e[i^1].f+=dd;
                ret+=dd;low-=dd;
            }
        }
        if (!ret) dis[x]=inf;
        return ret;
    }
    bool check(long long x)
    {
        build(x);
        long long max_flow=0,ret=0;
        while (bfs())
            max_flow+=dinic(s,inf);
        for (long long i=1;i<=n;i++)
            for (long long j=1;j<=m;j++)
                if (col[i][j]) ret+=(x-map[i][j]);
        if (ret==max_flow) return true;
        return false;
    }
    void work1()
    {
        long long x=(s1-s2)/(n1-n2);
        if (x>=mx)
            if (check(x))
            {
                long long ret=x*(n1+n2)-s1-s2;
                printf("%lld
    ",(x*(n1+n2)-s1-s2)/2);
                return;
            }
        printf("-1
    ");
    }
    void work2()
    {
        if (s1!=s2) {printf("-1
    ");return;}
        long long l=mx,r=inf,ans=inf;
        while (l<=r)
        {
            long long mid=l+r>>1;
            if (check(mid)) {ans=mid;r=mid-1;}
            else l=mid+1;
        }
        if (ans==inf) printf("-1
    ");
        else printf("%lld
    ",(ans*(n1+n2)-s1-s2)/2);
        return;
    }
    void work()
    {
        n1=0;n2=0;s1=0;s2=0;mx=0;
        scanf("%lld%lld",&n,&m);
        for (long long i=1;i<=n;i++)
            for (long long j=1;j<=m;j++)
            {
                scanf("%lld",&map[i][j]);
                mx=max(mx,map[i][j]);
            }
        if ((n==1) && (m==1)) 
        {
            printf("0
    ");
            return;
        }
        col[1][1]=1;
        for (long long i=1;i<=n;i++)
            for (long long j=1;j<=m;j++)
                for (long long k=1;k<=4;k++)
                    col[i+dx[k]][j+dy[k]]=col[i][j]^1;
        for (long long i=1;i<=n;i++)
            for (long long j=1;j<=m;j++)
            {
                if (col[i][j]) {n1++;s1+=map[i][j];}
                else {n2++;s2+=map[i][j];}
            }
        if (n1!=n2) work1();
        else work2();
    }
    int main()
    {
        scanf("%lld",&tt);
        for (long long i=1;i<=tt;i++)
            work();
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/ziliuziliu/p/5927275.html
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