题目描述:
Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1 / 2 3 5
All root-to-leaf paths are:
["1->2->5", "1->3"]
解题思路:
使用递归法。
代码如下:
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public List<String> binaryTreePaths(TreeNode root) { List<String> res = new ArrayList<String>(); if(root != null) searchTree(res, root, ""); return res; } public void searchTree(List<String> res, TreeNode root, String connection){ if(root.left == null && root.right == null) res.add(connection + root.val); if(root.left != null) searchTree(res, root.left, connection + root.val + "->"); if(root.right != null) searchTree(res, root.right, connection + root.val + "->"); } }