• HDU_1455_dfs


    http://acm.hdu.edu.cn/showproblem.php?pid=1455

    int dfs(int all,int sum,int now),all代表剩余总长,sum,代表每段长,now代表当前拼接的长度。

    if(a[i]+now == sum || now == 0) return 0;
    while(a[i+1] == a[i]) i++;

    这两句话剪枝很重要。

    #include<iostream>
    #include<string>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    
    int a[55],used[55],n;
    
    bool cmp(int a,int b)
    {
        return a>b;
    }
    
    int dfs(int all,int sum,int now)
    {
        if(all == 0 && now == sum)  return 1;
        if(now == sum)  now = 0;
        for(int i = 1;i <= n;i++)
        {
            if(used[i] || a[i]+now > sum)   continue;
            used[i] = 1;
            if(dfs(all-a[i],sum,now+a[i]))  return 1;
            used[i] = 0;
            if(a[i]+now == sum || now == 0) return 0;
            while(a[i+1] == a[i])   i++;
        }
        return 0;
    }
    int main()
    {
        while(cin >> n && n)
        {
            int sum = 0;
            for(int i = 1;i <= n;i++)
            {
                cin >> a[i];
                sum += a[i];
            }
            sort(a+1,a+n+1,cmp);
            for(int i = a[1];i <= sum;i++)
            {
                if(sum%i)   continue;
                memset(used,0,sizeof(used));
                if(dfs(sum,i,0))
                {
                    cout << i << endl;
                    break;
                }
            }
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zhurb/p/5873700.html
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