• A1147. Heaps


    In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))

    Your job is to tell if a given complete binary tree is a heap.

    Input Specification:

    Each input file contains one test case. For each case, the first line gives two positive integers: M (≤ 100), the number of trees to be tested; and N (1 < N ≤ 1,000), the number of keys in each tree, respectively. Then M lines follow, each contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.

    Output Specification:

    For each given tree, print in a line Max Heap if it is a max heap, or Min Heap for a min heap, or Not Heap if it is not a heap at all. Then in the next line print the tree's postorder traversal sequence. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line.

    Sample Input:

    3 8
    98 72 86 60 65 12 23 50
    8 38 25 58 52 82 70 60
    10 28 15 12 34 9 8 56
    

    Sample Output:

    Max Heap
    50 60 65 72 12 23 86 98
    Min Heap
    60 58 52 38 82 70 25 8
    Not Heap
    56 12 34 28 9 8 15 10


    #include<iostream>
    #include<cstdio>
    using namespace std;
    int N, M, tree[10010];
    int isMaxheap(){
        for(int k = N / 2; k >= 1; k--){
            int max;
            if(2*k + 1 <= N && tree[2*k+1] > tree[2*k]){
                max = tree[2*k + 1];
            }else{
                max = tree[2*k];
            }
            if(tree[k] < max)
                return 0;
        }
        return 1;
    }
    int isMinheap(){
        for(int k = N / 2; k >= 1; k--){
            int min;
            if(2*k+1 <= N && tree[2*k+1] < tree[2*k]){
                min = tree[2*k+1];
            }else min = tree[2*k];
            if(tree[k] > min)
                return 0;
        }
        return 1;
    }
    int cnt = 0;
    void postOrder(int root){
        if(root > N)
            return;
        postOrder(root*2);
        postOrder(root*2 + 1);
        cnt++;
        if(cnt == N)
            printf("%d
    ", tree[root]);
        else printf("%d ", tree[root]);
    }
    int main(){
        scanf("%d%d", &M, &N);
        for(int i = 0; i < M; i++){
            for(int i = 1; i <= N; i++){
                scanf("%d", &tree[i]);
            }
            if(isMaxheap()){
                printf("Max Heap
    ");
            }else if(isMinheap()){
                printf("Min Heap
    ");
            }else{
                printf("Not Heap
    ");
            }
            cnt = 0;
            postOrder(1);
        }
        cin >> N;
        return 0;
    }
    View Code

    总结:

    1、题意:检查每个给出的序列是否是一个大根堆或者小根堆。

  • 相关阅读:
    java乱码问题解决
    发送邮件工具方法
    MD5加密算法工具类
    2015年4月与5月
    Hark的数据结构与算法练习之煎饼排序
    Hark的数据结构与算法练习之图书馆排序
    Hark的数据结构与算法练习之耐心排序
    Hark的数据结构与算法练习之多路归并排序
    Hark的数据结构与算法练习之若领图排序ProxymapSort
    启动mysql出现了error the server quit without updating pid file (/var/lib/mysql/localhost.localdomain.pid)
  • 原文地址:https://www.cnblogs.com/zhuqiwei-blog/p/9569780.html
Copyright © 2020-2023  润新知