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    BigNumber

      1 #include <iostream>
      2 #include <cstdio>
      3 #include <string>
      4 #include <cstring>
      5 #include <algorithm>
      6 using namespace std;
      7 const int maxlen=3100;
      8 struct bigint
      9 {
     10     int a[maxlen],len;
     11     bigint()
     12     {
     13         memset(a,0,sizeof a);
     14         len=1;
     15     }
     16     bigint(string str)
     17     {
     18         memset(a,0,sizeof a);
     19         len=str.length();
     20         for(int i=1;i<=len;i++)a[i]=str[len-i]-'0';
     21     }
     22     bigint(int num)
     23     {
     24         memset(a,0,sizeof a);
     25         len=0;
     26         if(num==0)len++;
     27         else while(num)a[++len]=num%10,num/=10;
     28     }
     29     string tostring()
     30     {
     31         string str;
     32         for(int i=len;i;i--)str+=char(a[i]+'0');
     33         return str;
     34     }
     35     inline int& operator[](int num){return a[num];}
     36     friend bool operator<(bigint& a,bigint& b)
     37     {
     38         if(a.len>b.len)return false;
     39         if(a.len<b.len)return true;
     40         for(int i=a.len;i;i--)
     41         {
     42             if(a[i]>b[i])return false;
     43             if(a[i]<b[i])return true;
     44         }
     45         return false;
     46     }
     47     friend bool operator>(bigint& a,bigint& b){return b<a;}
     48     friend bool operator==(bigint& a,bigint& b)
     49     {
     50         if(a.len!=b.len)return false;
     51         for(int i=1;i<=a.len;i++)if(a[i]!=b[i])return false;
     52         return true;
     53     }
     54     friend bool operator>=(bigint& a,bigint& b){return !(a<b);}
     55     friend bool operator<=(bigint& a,bigint& b){return !(a>b);}
     56     friend bigint operator+(bigint& a,bigint& b)
     57     {
     58         bigint c;c.len=max(a.len,b.len);
     59         for(int i=1;i<=c.len;i++)c[i]=a[i]+b[i];
     60         for(int i=1;i<=c.len;i++)
     61             if(c[i]>=10)c[i]-=10,c[i+1]++;
     62         while(c[c.len+1])
     63         {
     64             c.len++;
     65             if(c[c.len]>=10)c[c.len]-=10,c[c.len+1]++;
     66         }
     67         return c;
     68     }
     69     friend bigint& operator+=(bigint& a,bigint& b){return a=a+b;}
     70     friend bigint operator-(bigint& a,bigint& b)
     71     {
     72         bigint c;c.len=a.len;
     73         for(int i=1;i<=c.len;i++)c[i]=a[i]-b[i];
     74         for(int i=1;i<=c.len;i++)
     75             if(c[i]<0)c[i]+=10,c[i+1]--;
     76         while(c.len&&!c[c.len])c.len--;
     77         if(!c.len)c.len=1;
     78         return c;
     79     }
     80     friend bigint& operator-=(bigint& a,bigint& b){return a=a-b;}
     81     friend bigint operator*(bigint& a,int b)
     82     {
     83         bigint c;c.len=a.len;
     84         for(int i=1;i<=c.len;i++)c[i]=a[i]*b;
     85         for(int i=1;i<=c.len;i++)c[i+1]+=c[i]/10,c[i]%=10;
     86         while(c[c.len+1])c.len++,c[c.len+1]+=c[c.len]/10,c[c.len]%=10;
     87         return c;
     88     }
     89     friend bigint operator*(int b,bigint& a){return a*b;}
     90     friend bigint operator*=(bigint& a,int b){a=a*b;return a;}
     91     friend bigint operator*(bigint a,bigint b)
     92     {
     93         bigint c;c.len=a.len+b.len-1;
     94         for(int i=1;i<=a.len;i++)
     95             for(int j=1;j<=b.len;j++)
     96             c[i+j-1]+=a[i]*b[j];
     97         for(int i=1;i<=c.len;i++)c[i+1]+=c[i]/10,c[i]%=10;
     98         while(c[c.len+1])c.len++,c[c.len+1]+=c[c.len]/10,c[c.len]%=10;
     99         return c;
    100     }
    101     friend bigint operator*=(bigint& a,bigint b){a=a*b;return a;}
    102     friend bigint operator/(bigint& a,int b)
    103     {
    104         bigint c;c.len=a.len;
    105         int d=0;
    106         for(int i=a.len;i;i--)d=d*10+a[i],c[i]+=d/b,d%=b;
    107         while(c.len&&!c[c.len])c.len--;
    108         if(!c.len)c.len=1;
    109         return c;
    110     }
    111     friend int operator%(bigint& a,int b)
    112     {
    113         int d=0;
    114         for(int i=a.len;i;i--)d=(d*10+a[i])%b;
    115         return d;
    116     }
    117     friend bigint operator/(bigint& a,bigint& b)
    118     {
    119         bigint c,d;c.len=a.len;
    120         for(int i=a.len;i;i--)
    121         {
    122             d*=10;d[1]+=a[i];
    123             while(d>=b)d-=b,c[i]++;
    124         }
    125         while(c.len&&!c[c.len])c.len--;
    126         if(!c.len)c.len=1;
    127         return c;
    128     }
    129     friend bigint operator%(bigint& a,bigint& b)
    130     {
    131         bigint d;
    132         for(int i=a.len;i;i--)
    133         {
    134             d*=10;d[1]+=a[i];
    135             while(d>=b)d-=b;
    136         }
    137         return d;
    138     }
    139     
    140 };
    141 void div(bigint& a,int b,bigint& p,int &c)
    142 {
    143     memset(p.a,0,sizeof p.a);p.len=a.len;c=0;
    144     for(int i=a.len;i;i--)
    145     {
    146         c=c*10+a[i];
    147         p[i]+=c/b;
    148         c%=b;
    149     }
    150     while(p.len&&!p[p.len])p.len--;
    151     if(!p.len)p.len=1;
    152 }
    153 bigint gcd(bigint a,bigint b)
    154 {
    155     while(!(b.len==1&&b[1]==0))a=a%b,swap(a,b);
    156     return a;
    157 }
    158 int main(int argc, char *argv[])
    159 {
    160     
    161     return 0;
    162 }

    SuffixArray

     1 #include <iostream>
     2 #include <cstdio>
     3 #include <string>
     4 #include <cstring>
     5 #include <algorithm>
     6 using namespace std;
     7 const int maxlen=310000;
     8 inline int change(char ch){return ch-'a';}
     9 int rank[maxlen],sa[maxlen];
    10 int trank[maxlen],tsa[maxlen];
    11 int isort[maxlen];
    12 int height[maxlen];
    13 void suffix_array(string str)
    14 {
    15     int len=str.length();str="&"+str;
    16     for(int i=1;i<=len;i++)isort[change(str[i])]++;
    17     for(int i=change('a')+1;i<=change('z');i++)isort[i]+=isort[i-1];
    18     for(int i=len;i;i--)sa[isort[change(str[i])]--]=i;
    19     for(int i=1;i<=len;i++)rank[sa[i]]=rank[sa[i-1]]+(str[sa[i]]!=str[sa[i-1]]);
    20     for(int o=1;o<=2*len;o*=2)
    21     {
    22         for(int i=1;i<=len;i++)isort[i]=0;
    23         for(int i=1;i<=len;i++)isort[rank[i+o]]++;
    24         for(int i=1;i<=len;i++)isort[i]+=isort[i-1];
    25         for(int i=len;i;i--)tsa[isort[rank[i+o]]--]=i;
    26         for(int i=1;i<=len;i++)isort[i]=0;
    27         for(int i=1;i<=len;i++)isort[rank[i]]++;
    28         for(int i=1;i<=len;i++)isort[i]+=isort[i-1];
    29         for(int i=len;i;i--)sa[isort[rank[tsa[i]]]--]=tsa[i];
    30         for(int i=1;i<=len;i++)trank[sa[i]]=trank[sa[i-1]]
    31                 +(rank[sa[i]]>rank[sa[i-1]]||rank[sa[i]+o]>rank[sa[i-1]+o]);
    32         for(int i=1;i<=len;i++)rank[i]=trank[i];
    33     }
    34     for(int i=1;i<=len;i++)
    35         if(rank[i]!=len)
    36         {
    37             while(str[i+height[rank[i]]]==str[sa[rank[i]+1]+height[rank[i]]])height[rank[i]]++;
    38             height[rank[i+1]]=max(height[rank[i]]-1,0);
    39         }
    40 }
    41 int main(int argc, char *argv[])
    42 {
    43     
    44     return 0;
    45 }

    Aho-Corasick automaton

     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 #include <string>
     5 #include <algorithm>
     6 using namespace std;
     7 inline int change(char ch)
     8 {
     9     if(ch=='A')return 0;
    10     if(ch=='T')return 1;
    11     if(ch=='G')return 2;
    12     if(ch=='C')return 3;
    13 }
    14 struct node{int s[4],fail;bool isend;}t[2100];int tnum;
    15 void add(string str)
    16 {
    17     int now=0;
    18     for(int i=0;i<str.length();i++)
    19     {
    20         if(!t[now].s[change(str[i])])
    21             t[now].s[change(str[i])]=++tnum;
    22         now=t[now].s[change(str[i])];
    23     }
    24     t[now].isend=true;
    25 }
    26 int q[2100],l,r;
    27 void getfail()
    28 {
    29     l=1;r=0;
    30     for(int i=0;i<4;i++)
    31         if(t[0].s[i])q[++r]=t[0].s[i];
    32     while(l<=r)
    33         for(int now=q[l++],i=0;i<4;i++)
    34         if(t[now].s[i])
    35         {
    36             t[t[now].s[i]].fail=t[now].fail;
    37             while(t[t[now].s[i]].fail&&!t[t[t[now].s[i]].fail].s[i])
    38                 t[t[now].s[i]].fail=t[t[t[now].s[i]].fail].fail;
    39             t[t[now].s[i]].fail=t[t[t[now].s[i]].fail].s[i];
    40             t[t[now].s[i]].isend|=t[t[t[now].s[i]].fail].isend;
    41             q[++r]=t[now].s[i];
    42         }
    43 }
    44 int main(int argc, char *argv[])
    45 {
    46     
    47     return 0;
    48 }

    Dinic

     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 #include <algorithm>
     5 using namespace std;
     6 const int maxpoint=110000,maxedge=1100000,inf=2147483647;
     7 int head[maxpoint],nowhead[maxpoint],pointsize;
     8 struct edge{int to,next,c;}g[maxedge];int gnum=1;
     9 void addedge(int from,int to,int c)
    10 {
    11     g[++gnum].to=to;g[gnum].c=c;g[gnum].next=head[from];head[from]=gnum;
    12     g[++gnum].to=from;g[gnum].c=0;g[gnum].next=head[to];head[to]=gnum;
    13 }
    14 int dfsstart,dfsend;
    15 int d[maxpoint];
    16 int q[maxpoint],ql,qr;
    17 bool BFS()
    18 {
    19     for(int i=1;i<=pointsize;i++)d[i]=0,nowhead[i]=head[i];
    20     q[ql=qr=1]=dfsend;
    21     while(ql<=qr)
    22         for(int now=q[ql++],i=head[now];i;i=g[i].next)
    23             if(g[i^1].c&&g[i].to!=dfsend&&!d[g[i].to])
    24                 d[q[++qr]=g[i].to]=d[now]+1;
    25     return d[dfsstart];
    26 }
    27 int DFS(int po,int delta)
    28 {
    29     if(po==dfsend)return delta;
    30     int nowans=0,t;
    31     for(int&i=nowhead[po];i&&delta;i=g[i].next)
    32         if(g[i].c&&d[g[i].to]+1==d[po]&&(t=DFS(g[i].to,min(delta,g[i].c))))
    33             g[i].c-=t,g[i^1].c+=t,delta-=t,nowans+=t;
    34     return nowans;
    35 }
    36 int dinic(int start,int end)
    37 {
    38     dfsstart=start,dfsend=end;
    39     int ans=0;
    40     while(BFS())ans+=DFS(start,inf);
    41     return ans;
    42 }
    43 int main(int argc, char *argv[])
    44 {
    45     
    46     return 0;
    47 }

    MincostMaxflow-Dinic

     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 #include <algorithm>
     5 using namespace std;
     6 const int maxpoint=110000,maxedge=1100000,inf=2147483647;
     7 int head[maxpoint],pointsize;
     8 struct edge{int to,next,c,p;}g[maxedge];int gnum=1;
     9 void addedge(int from,int to,int c,int p)
    10 {
    11     g[++gnum].to=to;g[gnum].c=c;g[gnum].p=p;g[gnum].next=head[from];head[from]=gnum;
    12     g[++gnum].to=from;g[gnum].c=0;g[gnum].p=-p;g[gnum].next=head[to];head[to]=gnum;
    13 }
    14 int dfsstart,dfsend;
    15 int d[maxpoint];
    16 bool havevis[maxpoint],isin[maxpoint];
    17 const int maxq=(1<<18)-1;
    18 int q[maxq+1],ql,qr;
    19 inline int inc(int&num){int temp=num;num=(num+1)&maxq;return temp;}
    20 bool SPFA()
    21 {
    22     for(int i=1;i<=pointsize;i++)d[i]=inf;
    23     ql=qr=0;d[q[inc(qr)]=dfsstart]=0;isin[dfsstart]=true;
    24     while(ql!=qr)
    25     {
    26         int now=q[inc(ql)];
    27         for(int i=head[now];i;i=g[i].next)
    28             if(g[i].c&&d[g[i].to]>d[now]+g[i].p)
    29             {
    30                 d[g[i].to]=d[now]+g[i].p;
    31                 if(!isin[g[i].to])isin[q[inc(qr)]=g[i].to]=true;
    32             }
    33         isin[now]=false;
    34     }
    35     return d[dfsend]<inf;
    36 }
    37 bool haveans;
    38 int flow,cost,dfsans;
    39 void DFS(int po)
    40 {
    41     havevis[po]=true;
    42     if(po==dfsend){flow+=dfsans;haveans=true;return ;}
    43     int tans=dfsans;
    44     for(int i=head[po];i;i=g[i].next)
    45         if(g[i].c&&d[g[i].to]==d[po]+g[i].p&&!havevis[g[i].to])
    46         {
    47             dfsans=min(dfsans,g[i].c);
    48             DFS(g[i].to);
    49             if(haveans)
    50             {
    51                 g[i].c-=dfsans,g[i^1].c+=dfsans;
    52                 cost+=dfsans*g[i].p;
    53                 return ;
    54             }
    55             dfsans=tans;
    56         }
    57 }
    58 void dinic(int start,int end)
    59 {
    60     dfsstart=start,dfsend=end;
    61     cost=flow=0;
    62     while(SPFA())
    63     {
    64         haveans=true;
    65         while(haveans)
    66         {
    67             for(int i=1;i<=pointsize;i++)havevis[i]=false;
    68             haveans=false;dfsans=inf;
    69             DFS(start);
    70         }
    71     }
    72 }
    73 int main(int argc ,char *argv[])
    74 {
    75     
    76     return 0;
    77 }

    NumberTheory

     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cmath>
     4 #include <cstring>
     5 #include <algorithm>
     6 using namespace std;
     7 typedef long long LL;
     8 namespace Online
     9 {
    10     inline int getnextfactor(int num)
    11     {
    12         for(int i=2,sqrtnum=(int)sqrt(num);i<=sqrtnum;i++)
    13             if(num%i==0)return i;
    14         return num;
    15     }
    16     int phi(int num)
    17     {
    18         if(num<=1)return 0;
    19         int ans=num;
    20         while(num>1)
    21         {
    22             int q=getnextfactor(num);
    23             ans=ans/q*(q-1);
    24             while(num%q==0)num/=q;
    25         }
    26         return ans;
    27     }
    28     LL gcd(LL a,LL b){return b?gcd(b,a%b):a;}
    29     LL exgcd(LL a,LL b,LL&x,LL&y)
    30     {
    31         if(!b){x=1,y=0;return a;}
    32         else{LL g=exgcd(b,a%b,x,y),t=x;x=y;y=t-a/b*y;return g;}
    33     }
    34 }
    35 namespace Offline
    36 {
    37     const int maxsize=210000;
    38     int prime[maxsize],pnum;
    39     bool isprime[maxsize];
    40     int phi[maxsize];
    41     void getlist(int listsize)
    42     {
    43         for(int i=2;i<=listsize;i++)isprime[i]=true;
    44         for(int i=2;i<=listsize;i++)
    45         {
    46             if(isprime[i])phi[prime[++pnum]=i]=i-1;
    47             for(int j=1;j<=pnum&&i*prime[j]<=listsize;j++)
    48             {
    49                 isprime[i*prime[j]]=false;
    50                 if(i%prime[j]==0)
    51                 {
    52                     phi[i*prime[j]]=phi[i]*prime[j];
    53                     break;
    54                 }
    55                 phi[i*prime[j]]=phi[i]*phi[prime[j]];
    56             }
    57         }
    58     }
    59 }
    60 namespace Mod_equation
    61 {
    62     int n;
    63     LL a[21000],b[21000];
    64     //x=a (mod b);
    65     LL la,lb;
    66     void solve()
    67     {
    68         la=a[1];lb=b[1];
    69         for(int i=2;i<=n;i++)
    70         {
    71             LL na=a[i],nb=b[i];
    72             LL p,q,g=Online::exgcd(lb,nb,p,q),d=na-la;
    73             if(d%g)return ;
    74             LL t=nb/g;p=(p*d/g%t+t)%t;
    75             la+    =lb*p;lb=nb*lb/g;
    76         }
    77     }
    78 }
    79 int main(int argc, char *argv[])
    80 {
    81     
    82     return 0;
    83 }

    Tarjan(强连通)

     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 #include <algorithm>
     5 using namespace std;
     6 const int maxpoint=11000,maxedge=51000;
     7 int n,m;
     8 struct point{int head,dfn,low,wk,instack;}p[maxpoint];
     9 struct edge{int next,to;}g[maxedge];int gnum;
    10 void addedge(int from,int to)
    11 {
    12     g[++gnum].to=to;g[gnum].next=p[from].head;p[from].head=gnum;
    13 }
    14 struct block{int size;}b[maxpoint];int bnum;
    15 int dfsnum;
    16 int s[maxpoint],sr=0;
    17 void tarjan(int po)
    18 {
    19     p[po].dfn=p[po].low=++dfsnum;
    20     p[s[++sr]=po].instack=true;
    21     for(int i=p[po].head;i;i=g[i].next)
    22     {
    23         if(!p[g[i].to].dfn)
    24             tarjan(g[i].to),p[po].low=min(p[po].low,p[g[i].to].low);
    25         else if(p[g[i].to].instack)
    26             p[po].low=min(p[po].low,p[g[i].to].dfn);
    27     }
    28     if(p[po].dfn==p[po].low)
    29     {
    30         bnum++;
    31         while(s[sr]!=po)p[s[sr]].instack=false,b[p[s[sr--]].wk=bnum].size++;
    32         p[s[sr]].instack=false,b[p[s[sr--]].wk=bnum].size++;
    33     }
    34 }
    35 int main(int argc, char *argv[])
    36 {
    37     
    38     return 0;
    39 }

    Link-Cut Tree

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    using namespace std;
    struct node{int s[2],f,ws,rev;}p[210000];
    inline void maintain(int po){}
    inline void setson(int f,int s,int ws){p[p[f].s[p[s].ws=ws]=s].f=f;}
    inline bool isroot(int po){return (!p[po].f)||(p[p[po].f].s[0]!=po&&p[p[po].f].s[1]!=po);}
    inline void rotate(int po,int ws)
    {
        int son=p[po].s[ws];
        if(isroot(po))p[son].f=p[po].f;
        else setson(p[po].f,son,p[po].ws);
        setson(po,p[son].s[!ws],ws);
        setson(son,po,!ws);
        maintain(po);maintain(son);
    }
    inline void reverse(int po)
    {
        if(p[po].rev)
        {
            swap(p[po].s[0],p[po].s[1]);
            p[p[po].s[0]].ws^=1,p[p[po].s[1]].ws^=1;
            p[p[po].s[0]].rev^=1,p[p[po].s[1]].rev^=1;
            p[po].rev^=1;
        }
    }
    inline int splay(int po)
    {
        while(!isroot(po))
        {
            int fa=p[po].f,gf=p[fa].f;
            reverse(gf);reverse(fa);reverse(po);
            if(isroot(fa)){rotate(fa,p[po].ws);break;}
            if(p[po].ws==p[fa].ws)rotate(gf,p[fa].ws);
            rotate(fa,p[po].ws);
        }
        reverse(po);maintain(po);
        return po;
    }
    inline void access(int po)
    {
        for(int last=0;po;last=po,po=p[po].f)
            splay(po),setson(po,last,1),maintain(po);
    }
    inline void makeroot(int po){access(po);splay(po);p[po].rev^=1;}
    inline void link(int u,int v){makeroot(u);p[u].f=v;}
    inline void cut(int u,int v){makeroot(u);access(u);splay(v);p[v].f=0;}
    int main(int argc, char *argv[])
    {
        
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zhuohan123/p/3413233.html
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