提取多层嵌套Json数据

在.net 2.0中提取这样的json  
{"name":"lily","age":23,"addr":{"city":guangzhou,"province":guangdong}}  
引用命名空间  
using Newtonsoft.Json;  
using Newtonsoft.Json.Linq;  
可以把上面的JSON看成一个对象.你只要写对应的类即可  
public class UserInfo  
{  
public string name;  
public int age;  
public address addr;  
}  
public class address  
{  
public string city;  
public string province;  
}  
然后在解析的地方这样写:  
string jsonData="{"name":"lily","age":23,"addr":{"city":guangzhou,"province":guangdong}}";  
UserInfo user=(UserInfo)JsonConvert.DeserializeObject(jsonData, typeof(UserInfo));  
得到City的值只要:user.addr.City;  
这样实现也行  
JObject jsonObj = JObject.Parse(jsonData);  
string name=jsonObj ["name"].ToString();  
string age=jsonObj ["age"].ToString();  
string city=((JObject )jsonObj ["addr"])["city"].ToString();  
string province=((JObject )jsonObj ["addr"])["province"].ToString();  
如何这个json是动态的呢？譬如让你输入一个json，如{"name":"lily","age":23,"addr":{"city":guangzhou,"province":guangdong}}； 然后让你输入一个对象，如city，然后系统会输出guangzhou这个值，那这样的话，json就是动态生成的了，我想了解有没有读取这样的json的方法。（注意，json是多级嵌套的。）  
就用遍历  
public string GetJsonValue(JEnumerable<JToken> jToken,string key)  
{  
IEnumerator enumerator = jToken.GetEnumerator();  
while (enumerator.MoveNext())  
{  
JToken jc = (JToken)enumerator.Current;  
  
if (jc is JObject||((JProperty)jc).Value is JObject)  
{  
return GetJsonValue(jc.Children(), key);  
}  
else  
{  
if (((JProperty)jc).Name == key)  
{  
return ((JProperty)jc).Value.ToString();  
}  
}  
}  
return null;  
}  
在调用的时候:  
string jsonData = "{"name":"lily","age":23,"addr":{"city":"guangzhou","province":"guangdong"}}";  
JObject jsonObj = JObject.Parse(jsonData);  
Response.Write(GetJsonValue(jsonObj.Children(), "province"));  
如果有多层嵌套的数组  
string  jsonData = "{"addr":[{"city":"guangzhou","province":"guangdong"},{"city":"guiyang","province":"guizhou"}]}";  
JObject  jsonObj = JObject.Parse(jsonData);  
JArray  jar = JArray.Parse(jsonObj["addr"].ToString());  
JObject  j = JObject.Parse(jar[0].ToString());  
Response.Write(j["city"]);  
JSON转XML  
string xmlstr=((XmlDocument)JsonConvert.DeserializeXmlNode(jsonData)).InnerXml.ToString();