SZU Problem(A16):Three Jugs
Judge Info
- Memory Limit: 32768KB
- Case Time Limit: 10000MS
- Time Limit: 10000MS
- Judger: Number Only Judger
Description
Frogs start exploring the kingdom when the first frog land. Recently, explore teams find a locked door. There is no key to open the door, but there is a small altar in front of the door, and the inscription on a nearby wall tells them that they need to fill up a water jug with exactly K gallons of water, and put it on the altar to open the door. The inscription also informs them that they have only one chance at trying to open the door.
Explore teams have three water jugs of sizes A,B and C only, and limited water source. How can they open the door? The team leader first lists out the possible actions:
1)Fill up one of the jugs with water;
2)Empty one of the jugs ,pour from it back into the water source;
3)Pour from one jug into other till either the former is empty or the latter jug is full.
Task
You are required to write a program that finds out the minimum amount of water required to open the door.
Input
The first line of input contains , the number of test cases. There is one line only for each test case, it contains four positive integers, the first three integers specifying the sizes of the jugs that can be used, and the fourth integer represent the target that needs to be achieved. All integers are in the range [1, 100].
Output
For each test case, print a line contains the minimum amount of water required. If it is not achievable, output -1.
Sample Input
2 4 9 13 10 4 9 13 5
Sample Output
10 9
刚刚开始,没有思路,只有暴力解决,不用想,绝对超时啦~
超级长的代码,还是要秀秀哈哈哈,虽然超时,但数据测试过,都是对的
!!!
1 #include <iostream> 2 #include <queue> 3 #include <cstring> // memset() 4 #include <stdio.h> 5 using namespace std; 6 const int N = 105; 7 // 所用到的数组 8 int flag[N][N][N]; 9 priority_queue<int> result; // 存储结果的优先队列 10 int queuea[N*N*N]; 11 int queueb[N*N*N]; 12 int queuec[N*N*N]; 13 int queued[N*N*N]; 14 int main() 15 { 16 int t, a, b, c, goal, head, p, tempa, tempb, tempc, tempd, i, big; 17 cin >> t; 18 while( t-- ) 19 { 20 // 初始化 21 head = p = 0; 22 while( !result.empty() ) 23 result.pop(); 24 cin >> a >> b >> c >> goal; 25 big = max(a, max( b, c ) ); 26 for( i=goal; i<=a+b+c; i++ ) 27 { 28 memset( flag, 0, sizeof(flag) ); 29 queuea[p] = 0; 30 queueb[p] = 0; 31 queuec[p] = 0; 32 queued[p++] = i; 33 34 while( head < p ) 35 { 36 tempa = queuea[head]; 37 tempb = queueb[head]; 38 tempc = queuec[head]; 39 tempd = queued[head]; 40 41 if( tempa != 0 ) 42 { 43 if( tempa >= b-tempb ) // a罐罐中的水将b罐罐倒满后还有剩余 44 { 45 tempa -= (b-tempb); 46 tempb = b; 47 } 48 else // a罐罐中的水全部都没有了 49 { 50 tempb += tempa; 51 tempa = 0; 52 } 53 if( tempa+tempb+tempc == goal ) 54 { 55 result.push( tempa+tempb+tempc+tempd ); 56 goto END; 57 } 58 else if( flag[tempa][tempb][tempc] == 0 ) 59 { 60 flag[tempa][tempb][tempc] = 1; 61 queuea[p] = tempa; 62 queueb[p] = tempb; 63 queuec[p] = tempc; 64 queued[p++] = tempd; 65 } 66 } 67 68 tempa = queuea[head]; 69 tempb = queueb[head]; 70 tempc = queuec[head]; 71 tempd = queued[head]; 72 73 if( tempa != 0 ) 74 { 75 if( tempa >= c-tempc ) // a罐罐中的水将c罐罐倒满后还有剩余 76 { 77 tempa -= (c-tempc); 78 tempc = c; 79 } 80 else // a罐罐中的水全部都没有了 81 { 82 tempc += tempa; 83 tempa = 0; 84 } 85 if( tempa+tempb+tempc == goal ) 86 { 87 result.push( tempa+tempb+tempc+tempd ); 88 goto END; 89 } 90 else if( flag[tempa][tempb][tempc] == 0 ) 91 { 92 flag[tempa][tempb][tempc] = 1; 93 queuea[p] = tempa; 94 queueb[p] = tempb; 95 queuec[p] = tempc; 96 queued[p++] = tempd; 97 } 98 } 99 100 tempa = queuea[head]; 101 tempb = queueb[head]; 102 tempc = queuec[head]; 103 tempd = queued[head]; 104 if( tempa != 0 ) 105 { 106 tempd += tempa; 107 tempa = 0; 108 109 if( tempa+tempb+tempc == goal ) 110 { 111 result.push( tempa+tempb+tempc+tempd ); 112 goto END; 113 } 114 else if( flag[tempa][tempb][tempc] == 0 ) 115 { 116 flag[tempa][tempb][tempc] = 1; 117 queuea[p] = tempa; 118 queueb[p] = tempb; 119 queuec[p] = tempc; 120 queued[p++] = tempd; 121 } 122 } 123 124 tempa = queuea[head]; 125 tempb = queueb[head]; 126 tempc = queuec[head]; 127 tempd = queued[head]; 128 129 if( tempb != 0 ) 130 { 131 if( tempb >= a-tempa ) // b罐罐中的水将a罐罐倒满后还有剩余 132 { 133 tempb -= (a-tempa); 134 tempa = a; 135 } 136 else // b罐罐中的水全部都没有了 137 { 138 tempa += tempb; 139 tempb = 0; 140 } 141 if( tempa+tempb+tempc == goal ) 142 { 143 result.push( tempa+tempb+tempc+tempd ); 144 goto END; 145 } 146 else if( flag[tempa][tempb][tempc] == 0 ) 147 { 148 flag[tempa][tempb][tempc] = 1; 149 queuea[p] = tempa; 150 queueb[p] = tempb; 151 queuec[p] = tempc; 152 queued[p++] = tempd; 153 } 154 } 155 156 tempa = queuea[head]; 157 tempb = queueb[head]; 158 tempc = queuec[head]; 159 tempd = queued[head]; 160 161 if( tempb != 0 ) 162 { 163 if( tempb >= c-tempc ) // b罐罐中的水将c罐罐倒满后还有剩余 164 { 165 tempb -= (c-tempc); 166 tempc = c; 167 } 168 else // b罐罐中的水全部都没有了 169 { 170 tempc += tempb; 171 tempb = 0; 172 } 173 if( tempa+tempb+tempc == goal ) 174 { 175 result.push( tempa+tempb+tempc+tempd ); 176 goto END; 177 } 178 else if( flag[tempa][tempb][tempc] == 0 ) 179 { 180 flag[tempa][tempb][tempc] = 1; 181 queuea[p] = tempa; 182 queueb[p] = tempb; 183 queuec[p] = tempc; 184 queued[p++] = tempd; 185 } 186 } 187 188 tempa = queuea[head]; 189 tempb = queueb[head]; 190 tempc = queuec[head]; 191 tempd = queued[head]; 192 if( tempb != 0 ) 193 { 194 tempd += tempb; 195 tempb = 0; 196 197 if( tempa+tempb+tempc == goal ) 198 { 199 result.push( tempa+tempb+tempc+tempd ); 200 goto END; 201 } 202 else if( flag[tempa][tempb][tempc] == 0 ) 203 { 204 flag[tempa][tempb][tempc] = 1; 205 queuea[p] = tempa; 206 queueb[p] = tempb; 207 queuec[p] = tempc; 208 queued[p++] = tempd; 209 } 210 } 211 212 tempa = queuea[head]; 213 tempb = queueb[head]; 214 tempc = queuec[head]; 215 tempd = queued[head]; 216 217 if( tempc != 0 ) 218 { 219 if( tempc >= a-tempa ) // c罐罐中的水将a罐罐倒满后还有剩余 220 { 221 tempc -= (a-tempa); 222 tempa = a; 223 } 224 else // c罐罐中的水全部都没有了 225 { 226 tempa += tempc; 227 tempc = 0; 228 } 229 if( tempa+tempb+tempc == goal ) 230 { 231 result.push( tempa+tempb+tempc+tempd ); 232 goto END; 233 } 234 else if( flag[tempa][tempb][tempc] == 0 ) 235 { 236 flag[tempa][tempb][tempc] = 1; 237 queuea[p] = tempa; 238 queueb[p] = tempb; 239 queuec[p] = tempc; 240 queued[p++] = tempd; 241 } 242 } 243 244 tempa = queuea[head]; 245 tempb = queueb[head]; 246 tempc = queuec[head]; 247 tempd = queued[head]; 248 249 if( tempc != 0 ) 250 { 251 if( tempc >= b-tempb ) // c罐罐中的水将b罐罐倒满后还有剩余 252 { 253 tempc -= (b-tempb); 254 tempb = b; 255 } 256 else // c罐罐中的水全部都没有了 257 { 258 tempb += tempc; 259 tempc = 0; 260 } 261 if( tempa+tempb+tempc == goal ) 262 { 263 result.push( tempa+tempb+tempc+tempd ); 264 goto END; 265 } 266 else if( flag[tempa][tempb][tempc] == 0 ) 267 { 268 flag[tempa][tempb][tempc] = 1; 269 queuea[p] = tempa; 270 queueb[p] = tempb; 271 queuec[p] = tempc; 272 queued[p++] = tempd; 273 } 274 } 275 276 tempa = queuea[head]; 277 tempb = queueb[head]; 278 tempc = queuec[head]; 279 tempd = queued[head]; 280 if( tempc != 0 ) 281 { 282 tempd += tempc; 283 tempc = 0; 284 285 if( tempa+tempb+tempc == goal ) 286 { 287 result.push( tempa+tempb+tempc+tempd ); 288 goto END; 289 } 290 else if( flag[tempa][tempb][tempc] == 0 ) 291 { 292 flag[tempa][tempb][tempc] = 1; 293 queuea[p] = tempa; 294 queueb[p] = tempb; 295 queuec[p] = tempc; 296 queued[p++] = tempd; 297 } 298 } 299 300 tempa = queuea[head]; 301 tempb = queueb[head]; 302 tempc = queuec[head]; 303 tempd = queued[head]; 304 305 if( tempd != 0 && tempd >= a-tempa ) 306 { 307 tempd -= (a-tempa); 308 tempa = a; 309 310 if( tempa+tempb+tempc == goal ) 311 { 312 result.push( tempa+tempb+tempc+tempd ); 313 goto END; 314 } 315 else if( flag[tempa][tempb][tempc] == 0 ) 316 { 317 flag[tempa][tempb][tempc] = 1; 318 queuea[p] = tempa; 319 queueb[p] = tempb; 320 queuec[p] = tempc; 321 queued[p++] = tempd; 322 } 323 } 324 325 tempa = queuea[head]; 326 tempb = queueb[head]; 327 tempc = queuec[head]; 328 tempd = queued[head]; 329 330 if( tempd != 0 && tempd >= b-tempb ) 331 { 332 tempd -= (b-tempb); 333 tempb = b; 334 if( tempa+tempb+tempc == goal ) 335 { 336 result.push( tempa+tempb+tempc+tempd ); 337 goto END; 338 } 339 else if( flag[tempa][tempb][tempc] == 0 ) 340 { 341 flag[tempa][tempb][tempc] = 1; 342 queuea[p] = tempa; 343 queueb[p] = tempb; 344 queuec[p] = tempc; 345 queued[p++] = tempd; 346 } 347 } 348 349 tempa = queuea[head]; 350 tempb = queueb[head]; 351 tempc = queuec[head]; 352 tempd = queued[head]; 353 354 if( tempd != 0 && tempd >= c-tempc ) 355 { 356 tempd -= (c-tempc); 357 tempc = c; 358 359 if( tempa+tempb+tempc == goal ) 360 { 361 result.push( tempa+tempb+tempc+tempd ); 362 goto END; 363 } 364 else if( flag[tempa][tempb][tempc] == 0 ) 365 { 366 flag[tempa][tempb][tempc] = 1; 367 queuea[p] = tempa; 368 queueb[p] = tempb; 369 queuec[p] = tempc; 370 queued[p++] = tempd; 371 } 372 } 373 head++; 374 } 375 } 376 END: if( result.empty() == true ) 377 cout << -1 << endl; 378 else 379 cout << result.top() << endl; 380 } 381 return 0; 382 }
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1 #include <iostream> 2 #include <queue> 3 #include <cstring> // memset() 4 #include <stdio.h> 5 using namespace std; 6 const int N = 105; 7 // 所用到的数组 8 struct node 9 { 10 bool operator < ( const node& n1 ) const 11 { 12 return priority > n1.priority; // 最小值优先 13 } 14 int a; 15 int b; 16 int c; 17 int d; 18 int priority; 19 }; 20 int goal; 21 int flag[N][N][N]; 22 priority_queue< int, vector<int>, greater<int> > result; // 存储结果的优先队列 23 priority_queue< node > my_queue; 24 void judge( int, int, int, int ); 25 int main() 26 { 27 int t, a, b, c, tempa, tempb, tempc, tempd; 28 scanf( "%d", &t ); 29 while( t-- ) 30 { 31 // 初始化 32 while( !result.empty() ) 33 result.pop(); 34 while( !my_queue.empty() ) 35 my_queue.pop(); 36 scanf( "%d%d%d%d", &a, &b, &c, &goal ); 37 38 memset( flag, 0, sizeof(flag) ); 39 40 node begin; 41 begin.a = 0; 42 begin.b = 0; 43 begin.c = 0; 44 begin.d = goal; 45 flag[0][0][0] = 1; 46 begin.priority = goal; 47 my_queue.push( begin ); 48 while( my_queue.empty() != true ) 49 { 50 node temp = my_queue.top(); 51 tempa = temp.a; 52 tempb = temp.b; 53 tempc = temp.c; 54 tempd = temp.d; 55 56 57 if( tempa != 0 ) 58 { 59 if( tempa >= b-tempb ) // a罐罐中的水将b罐罐倒满后还有剩余 60 { 61 tempa -= (b-tempb); 62 tempb = b; 63 } 64 else // a罐罐中的水全部都没有了 65 { 66 tempb += tempa; 67 tempa = 0; 68 } 69 judge( tempa, tempb, tempc, tempd ); 70 } 71 72 tempa = temp.a; 73 tempb = temp.b; 74 tempc = temp.c; 75 tempd = temp.d; 76 77 if( tempa != 0 ) 78 { 79 if( tempa >= c-tempc ) // a罐罐中的水将c罐罐倒满后还有剩余 80 { 81 tempa -= (c-tempc); 82 tempc = c; 83 } 84 else // a罐罐中的水全部都没有了 85 { 86 tempc += tempa; 87 tempa = 0; 88 } 89 judge( tempa, tempb, tempc, tempd ); 90 } 91 92 tempa = temp.a; 93 tempb = temp.b; 94 tempc = temp.c; 95 tempd = temp.d; 96 if( tempa != 0 ) 97 { 98 tempd += tempa; 99 tempa = 0; 100 101 judge( tempa, tempb, tempc, tempd ); 102 } 103 104 tempa = temp.a; 105 tempb = temp.b; 106 tempc = temp.c; 107 tempd = temp.d; 108 109 if( tempb != 0 ) 110 { 111 if( tempb >= a-tempa ) // b罐罐中的水将a罐罐倒满后还有剩余 112 { 113 tempb -= (a-tempa); 114 tempa = a; 115 } 116 else // b罐罐中的水全部都没有了 117 { 118 tempa += tempb; 119 tempb = 0; 120 } 121 judge( tempa, tempb, tempc, tempd ); 122 } 123 124 tempa = temp.a; 125 tempb = temp.b; 126 tempc = temp.c; 127 tempd = temp.d; 128 129 if( tempb != 0 ) 130 { 131 if( tempb >= c-tempc ) // b罐罐中的水将c罐罐倒满后还有剩余 132 { 133 tempb -= (c-tempc); 134 tempc = c; 135 } 136 else // b罐罐中的水全部都没有了 137 { 138 tempc += tempb; 139 tempb = 0; 140 } 141 judge( tempa, tempb, tempc, tempd ); 142 } 143 144 tempa = temp.a; 145 tempb = temp.b; 146 tempc = temp.c; 147 tempd = temp.d; 148 if( tempb != 0 ) 149 { 150 tempd += tempb; 151 tempb = 0; 152 153 judge( tempa, tempb, tempc, tempd ); 154 } 155 156 tempa = temp.a; 157 tempb = temp.b; 158 tempc = temp.c; 159 tempd = temp.d; 160 161 if( tempc != 0 ) 162 { 163 if( tempc >= a-tempa ) // c罐罐中的水将a罐罐倒满后还有剩余 164 { 165 tempc -= (a-tempa); 166 tempa = a; 167 } 168 else // c罐罐中的水全部都没有了 169 { 170 tempa += tempc; 171 tempc = 0; 172 } 173 judge( tempa, tempb, tempc, tempd ); 174 } 175 176 tempa = temp.a; 177 tempb = temp.b; 178 tempc = temp.c; 179 tempd = temp.d; 180 181 if( tempc != 0 ) 182 { 183 if( tempc >= b-tempb ) // c罐罐中的水将b罐罐倒满后还有剩余 184 { 185 tempc -= (b-tempb); 186 tempb = b; 187 } 188 else // c罐罐中的水全部都没有了 189 { 190 tempb += tempc; 191 tempc = 0; 192 } 193 judge( tempa, tempb, tempc, tempd ); 194 } 195 196 tempa = temp.a; 197 tempb = temp.b; 198 tempc = temp.c; 199 tempd = temp.d; 200 if( tempc != 0 ) 201 { 202 tempd += tempc; 203 tempc = 0; 204 205 judge( tempa, tempb, tempc, tempd ); 206 } 207 208 tempa = temp.a; 209 tempb = temp.b; 210 tempc = temp.c; 211 tempd = temp.d; 212 213 if( tempd >= a-tempa ) 214 { 215 tempd -= (a-tempa); 216 tempa = a; 217 } 218 else if( a+tempb+tempc <= a+b+c ) 219 { 220 tempd = 0; 221 tempa = a; 222 } 223 224 judge( tempa, tempb, tempc, tempd ); 225 226 tempa = temp.a; 227 tempb = temp.b; 228 tempc = temp.c; 229 tempd = temp.d; 230 231 if( tempd >= b-tempb ) 232 { 233 tempd -= (b-tempb); 234 tempb = b; 235 } 236 else if( tempa+b+tempc <= a+b+c ) 237 { 238 tempd = 0; 239 tempb = b; 240 } 241 judge( tempa, tempb, tempc, tempd ); 242 243 tempa = temp.a; 244 tempb = temp.b; 245 tempc = temp.c; 246 tempd = temp.d; 247 248 249 if( tempd >= c-tempc ) 250 { 251 tempd -= (c-tempc); 252 tempc = c; 253 } 254 else if( tempa+tempb+c <= a+b+c ) 255 { 256 tempd = 0; 257 tempc = c; 258 } 259 judge( tempa, tempb, tempc, tempd ); 260 261 262 if( result.empty() == false ) 263 { 264 temp = my_queue.top(); 265 int a = result.top(); 266 if( a <= temp.priority ) 267 break; 268 else 269 my_queue.pop(); 270 } 271 else 272 my_queue.pop(); 273 } 274 if( result.empty() == true ) 275 cout << -1 << endl; 276 else 277 cout << result.top() << endl; 278 } 279 return 0; 280 } 281 void judge( int tempa, int tempb, int tempc, int tempd ) 282 { 283 node temp; 284 if( tempa+tempb+tempc == goal ) 285 result.push( tempa+tempb+tempc+tempd ); 286 else if( flag[tempa][tempb][tempc] == 0 ) 287 { 288 flag[tempa][tempb][tempc] = 1; 289 temp.a = tempa; 290 temp.b = tempb; 291 temp.c = tempc; 292 temp.d = tempd; 293 temp.priority = tempa+tempb+tempc+tempd; 294 my_queue.push( temp ); 295 } 296 }
最后,睡前一AC,心情倍儿棒,大家晚安吧~