• LeetCode--Group Anagrams


    LeetCode——Group Anagrams

    Question

    Given an array of strings, group anagrams together.

    For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"],
    Return:

    [
    ["ate", "eat","tea"],
    ["nat","tan"],
    ["bat"]
    ]
    Note: All inputs will be in lower-case.

    解题思路

    首先,想到的就是两个for循环一次比较,判断的时候,可以将两个字符串按照字母序排序,来判断两个是否相当,两个for循环,数量多的时候肯定是要超时的。时间复杂度为O(n^2).

    所以,这个道题考的是Hash算法,用Map实现,时间复杂度为O(n)。

    具体实现

    1. 一般解法:
    #include <iostream>
    #include <vector>
    #include <map>
    
    using namespace std;
    
    class Solution {
    public:
        vector<vector<string>> groupAnagrams(vector<string>& strs) {
            if (strs.empty())
                return vector<vector<string> >();
    
            int len = strs.size();
    
            vector<vector<string> > ret;
    
            for (int i = 0; i < len; i++)
            {
                if (strs[i].empty())
                    continue;
                vector<string > sv;
                string tmp1 = strs[i];
                sv.push_back(tmp1);
    
                sort(tmp1.begin(), tmp1.end());
                for (int j = i + 1; j < len; j++)
                {
                    string tmp2 = strs[j];
                    sort(tmp2.begin(), tmp2.end());
    
                    if (tmp1 == tmp2)
                    {
                        sv.push_back(strs[j]);
                        //将处理后的元素赋值为空
                        strs[j].erase(0, std::string::npos);
                    }
                }//for
    
                //按字典排序该序列
                sort(sv.begin(), sv.end());
                //添加到结果vector
                ret.push_back(sv);
    
            }//for
            return ret;
        }
    };
    
    
    int main() {
        vector<string> vec;
        vec.push_back("");
        vec.push_back("tea");
        vec.push_back("tan");
        vec.push_back("ate");
        vec.push_back("nat");
        vec.push_back("bat");
        Solution* solution = new Solution();
        vector<vector<string>> result = solution->groupAnagrams(vec);
        for (int i = 0; i < result.size(); i++) {
            for (int j = 0; j < result[i].size(); j++) {
                cout << result[i][j] << " ";
            }
            cout << endl;
        }
        return 0;
    }
    
    1. AC解法:
    #include <iostream>
    #include <vector>
    #include <map>
    
    using namespace std;
    
    class Solution {
    public:
        vector<vector<string>> groupAnagrams(vector<string>& strs) {
            if (strs.size() == 0)
                return vector<vector<string>>();
            int size = strs.size();
    
            vector<vector<string>> res;
    
            map<string, vector<string>> str_vec;
            for (int i = 0; i < size; i++) {
                string str = strs[i];
                sort(str.begin(), str.end());
                str_vec[str].push_back(strs[i]);
            }
            for (map<string, vector<string>>::iterator iter = str_vec.begin(); iter != str_vec.end(); iter++) {
                sort(iter->second.begin(), iter->second.end());
                res.push_back(iter->second);
            }
            return res;
        }
    };
    
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  • 原文地址:https://www.cnblogs.com/zhonghuasong/p/6574399.html
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