[数据结构]——桶排序

一，桶排序

以下代码转自：桶排序

#include <iostream>
 #include <list>

 using namespace std;

 struct Node
 {
     double value;
     Node *next;
 };
 //桶排序主程序
 void bucketSort(double* arr, int length)
 {
     Node key[10];
     int number = 0;
     Node *p, *q;//插入节点临时变量
     int counter = 0;
     for(int i = 0; i < 10; i++)
     {
         key[i].value = 0;
         key[i].next = NULL;
     }

     for(int i = 0; i < length; i++)
     {
         Node *insert = new Node();
         insert->value = arr[i];
         insert->next = NULL;
         number = arr[i] * 10;
         if(key[number].next == NULL)
         {
             key[number].next = insert;
         }
         else
         {
             p = &key[number];
             q = key[number].next;
             while((q != NULL) && (q->value <= arr[i]))
             {
                 q = q->next;
                 p = p->next;
             }
             insert->next = q;
             p->next = insert;
         }
     }
     for(int i = 0; i < 10; i++)
     {
         p = key[i].next;
         if(p == NULL)
             continue;
         while(p != NULL)
         {
             arr[counter++] = p->value;
             p = p->next;
         }
     }
 }

 int main()
 {
     double a[] = {0.78, 0.17, 0.39, 0.26, 0.72, 0.94, 0.21, 0.12, 0.23, 0.68};
     bucketSort(a, 10);
     for(int i = 0; i < 10; i++)
     {
         cout << a[i] << " ";
     }
     cout << endl;
     return 0;
 }

【例】要将一副混洗的52张扑克牌按点数A<2<…<J<Q<K排序，需设置13个"箱子"，排序时依次将每张牌按点数放入相应的箱子里，然后依次将这些箱子首尾相接，就得到了按点数递增序排列的一副
一般情况下每个箱子中存放多少个关键字相同的记录是无法预料的，故箱子的类型应设计成链表为宜。