本片题解设计两种解法
果然是签到题...
因为返回值问题T了好久...
第一眼：搜索大水题？
然后...竟然A了
1 #include<cstdio> 2 #include<queue> 3 #include<iostream> 4 #include<cstring> 5 #define int long long 6 using namespace std; 7 inline int read(){ 8 int ans=0,f=1;char chr=getchar(); 9 while(!isdigit(chr)){if(chr=='-') f=-1;chr=getchar();} 10 while(isdigit(chr)){ans=(ans<<3)+(ans<<1)+chr-48;chr=getchar();} 11 return ans*f; 12 }int fm,m,tot,a[105],x,ff,p[105],q[105]; 13 void dfs(int x,int now){ 14 if(ff) return; 15 if(x==0&&now>=m) return; 16 if(now<m){ 17 ff=1; 18 int t=100; 19 while(p[t]==0) t--; 20 cout<<t+1<<endl<<now<<" "; 21 for(int i=1;i<=t;i++) cout<<p[i]<<" "; 22 return; 23 } 24 int t=now/a[x]; 25 for(int i=t;i>=0;i--) p[x]=i,dfs(x-1,now-a[x]*i); 26 } 27 signed main(){ 28 m=read(),fm=read(); 29 x=1;a[0]=1; 30 while(x<fm&&tot<=101){a[++tot]=x*m;x=x*m;} 31 dfs(tot,fm); 32 return 0; 33 }
但其实只要分析一下，就发现式子跟进制转换有很大关系啊，我们只要把fm当做m进制数来处理即可
1 #include<cstdio> 2 #include<iostream> 3 #include<cstring> 4 #include<cmath> 5 #include<algorithm> 6 #include<cstdlib> 7 #include<ctime> 8 #define int long long 9 using namespace std; 10 inline int read(){ 11 int ans=0,f=1;char chr=getchar(); 12 while(!isdigit(chr)){if(chr=='-') f=-1;chr=getchar();} 13 while(isdigit(chr)){ans=(ans<<3)+(ans<<1)+chr-48;chr=getchar();} 14 return ans*f; 15 }void write(long long x){ 16 if(x < 0) putchar('-'),x = -x; 17 if(x > 9) write(x / 10); 18 putchar(x % 10 + '0'); 19 }int n,m,a[505],tot; 20 signed main(){ 21 m=read(),n=read(); 22 while(n){a[++tot]=n%m;n/=m;} 23 printf("%d ",tot); 24 for(int i=1;i<=tot;i++)write(a[i]),putchar(' '); 25 return 0; 26 }