• Gas Station


    There are N gas stations along a circular route, where the amount of gas at station i is gas[i].
    You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.
    Return the starting gas station's index if you can travel around the circuit once, otherwise return -1.
    The solution is guaranteed to be unique.

    Solution: ...

     1 class Solution {
     2 public:
     3     int canCompleteCircuit(vector<int> &gas, vector<int> &cost) {
     4         int N = gas.size();
     5         int res = 0, min = gas[0] - cost[0], sum = min;
     6         for (int i = 1; i < N; ++i)
     7         {
     8             sum += gas[i] - cost[i];
     9             if (sum < min) { // not understand it completely
    10                 min = sum;
    11                 res = i;
    12             }
    13         }
    14         return sum >= 0 ? (res + 1) % N : -1;
    15     }
    16 };
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  • 原文地址:https://www.cnblogs.com/zhengjiankang/p/3682324.html
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