• PAT-1058 A+B in Hogwarts (进制转换)


    1058. A+B in Hogwarts


    If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

    Input Specification:

    Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

    Output Specification:

    For each test case you should output the sum of A and B in one line, with the same format as the input.

    Sample Input:
    3.2.1 10.16.27
    
    Sample Output:
    14.1.28

    水题,可能唯一要注意的就是不能把所有位转换到最低位,然后对两个数相加再转换回去,因为这种方法可能会溢出。只需要从低位到高位依次相加,考虑进位即可。

    #include <cstdio>
    int main(void) {
        int g1, s1, k1, g2, s2, k2, g3, s3, k3, t;
        
        scanf("%d.%d.%d %d.%d.%d", &g1, &s1, &k1, &g2, &s2, &k2);
        k3 = (k1 + k2) % 29;
        t = s1 + s2 + (k1 + k2) / 29;   
        s3 = t % 17;
        g3 = g1 + g2 + t / 17;
        printf("%d.%d.%d
    ", g3, s3, k3);
        
        return 0;
    }


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  • 原文地址:https://www.cnblogs.com/zhayujie/p/7534851.html
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