题目链接:
题意:
现在一串小写的英文字符,每个字符可以变成它前边的字符即b-a,c-a,a-z这样,选一个字串变换,使得得到的字符串字典序最小;
思路:
贪心,尽量让前边的字典序变小;
AC代码:
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <bits/stdc++.h> #include <stack> #include <map> using namespace std; #define For(i,j,n) for(int i=j;i<=n;i++) #define mst(ss,b) memset(ss,b,sizeof(ss)); typedef long long LL; template<class T> void read(T&num) { char CH; bool F=false; for(CH=getchar();CH<'0'||CH>'9';F= CH=='-',CH=getchar()); for(num=0;CH>='0'&&CH<='9';num=num*10+CH-'0',CH=getchar()); F && (num=-num); } int stk[70], tp; template<class T> inline void print(T p) { if(!p) { puts("0"); return; } while(p) stk[++ tp] = p%10, p/=10; while(tp) putchar(stk[tp--] + '0'); putchar(' '); } const LL mod=1e9+7; const double PI=acos(-1.0); const int inf=1e9; const int N=1e5+10; const int maxn=1e3+20; const double eps=1e-12; char s[N]; int main() { scanf("%s",s); int len=strlen(s),flag=0; for(int i=0;i<len;i++) { if(s[i]!='a') { s[i]=s[i]-1; flag=1; continue; } else { if(flag==0)continue; else break; } } if(flag==0) { s[len-1]='z'; } for(int i=0;i<len;i++)printf("%c",s[i]); return 0; }