• leetcode-539-Minimum Time Difference


    leetcode-539-Minimum Time Difference

    539. Minimum Time Difference

    • Total Accepted: 3164
    • Total Submissions: 7087
    • Difficulty: Medium
    • Contributors: fallcreek

    Given a list of 24-hour clock time points in "Hour:Minutes" format, find the minimum minutes difference between any two time points in the list.

    Example 1:

    Input: ["23:59","00:00"]
    Output: 1
    

    Note:

    1. The number of time points in the given list is at least 2 and won't exceed 20000.
    2. The input time is legal and ranges from 00:00 to 23:59.

    Subscribe to see which companies asked this question.

    题解:

    简单的时钟问题; (1), 先对时间进行排序, (2),计算头尾即可

    class Solution {
    public:
        int GetNum(string tp){
            return (60*((tp[0]-'0')*10 + (tp[1]-'0')) + (tp[3]-'0')*10 + tp[4]-'0'); 
        } 
        int findMinDifference(vector<string>& timePoints) {
            int len = timePoints.size(); 
            if(len <= 1){
                return 0; 
            }
            sort(timePoints.begin(), timePoints.end()); 
            int tmp, ans = 24*60-GetNum(timePoints[len-1]) + GetNum(timePoints[0]); 
            for(int i=0; i<len-1; ++i){
                tmp = GetNum(timePoints[i+1]) - GetNum(timePoints[i]); 
                if(tmp < ans){
                    ans = tmp; 
                }
            }
            return ans; 
        }
    };
    

      

  • 相关阅读:
    alias 命令
    iptables 命令
    unzip 命令
    gzip 命令
    zip 命令
    tar 命令
    nslookup 命令
    dig 命令
    java 线程池
    java 线程
  • 原文地址:https://www.cnblogs.com/zhang-yd/p/6597224.html
Copyright © 2020-2023  润新知