• Codeforces Round #318 [RussianCodeCup Thanks-Round] (Div. 2)——B纯暴力——Bear and Three Musketeers


    /*
    写搜索WA了。。赛后发现直接暴力不会超啊,,,
    */
    /************************************************
    * Author        :Powatr
    * Created Time  :2015-8-30 14:55:10
    * File Name     :B.cpp
     ************************************************/
    
    #include <cstdio>
    #include <algorithm>
    #include <iostream>
    #include <sstream>
    #include <cstring>
    #include <cmath>
    #include <string>
    #include <vector>
    #include <queue>
    #include <deque>
    #include <stack>
    #include <list>
    #include <map>
    #include <set>
    #include <bitset>
    #include <cstdlib>
    #include <ctime>
    using namespace std;
    
    #define lson l, mid, rt << 1
    #define rson mid + 1, r, rt << 1 | 1
    typedef long long ll;
    const int MAXN = 4e3 + 10;
    const int INF = 0x3f3f3f3f;
    const int MOD = 1e9 + 7;
    
    int a[MAXN][MAXN];
    vector<int> G[MAXN];
    int main(){
        int n, m;
        while(~scanf("%d%d", &n, &m)){
            int x, y;
            memset(a, 0, sizeof(a));
            for(int i = 1; i <= n; i++)
                G[i].clear();
            for(int i = 1; i <= m; i++){
                scanf("%d%d", &x, &y);
                a[x][y] = a[y][x] = 1;
                G[x].push_back(y);
                G[y].push_back(x);
            }
            int min1 = INF;
            for(int i = 1; i <= n; i++){
                for(int j = i + 1; j <= n; j++){
                    if(a[i][j]){
                        for(int k = j + 1; k <= n; k++){
                            if(a[i][k] && a[k][j]){
                        int temp = G[i].size() + G[j].size() + G[k].size();
                                min1 = min(min1,temp);
                            }
                        }
                    }
                }
            }
            if(min1 == INF) puts("-1");
            else printf("%d
    ", min1 - 6);
        }
        return 0;
    }
    

      

  • 相关阅读:
    01Go语言的特性和优势
    03Go的执行原理及Go的常用命令
    05Go语言的程序流程结构
    00golong语言环境的安装与配置
    04变量、常量、运算符
    02GoLang Hello,World!
    java常用类
    Overview of Database Link数据库链接概述
    数据类型
    数据块概述
  • 原文地址:https://www.cnblogs.com/zero-begin/p/4770907.html
Copyright © 2020-2023  润新知