• CPP函数类型转换


    1. 类成员函数转成std::function及lambda

    class MyClass{
      pub:
        int Func(int a) {};
    };
    int main(void) {
        MyClass my_class;
        std::function<int(int a)> func_ = std::bind(&MyClass::Func, &my_class, std::placeholders::_1);
    
        auto lambda_func_ = [&my_class](int a) -> int {
            return my_class.Func(a);
        }
    }

     2. lambda转成std::function,参考https://www.cnblogs.com/qicosmos/p/4772328.html,做类型萃取,链接还讲了any class,有时间要看看。

    // g++ lambda_to_func.cpp -std=c++11 -Werror
    #include <cxxabi.h>
    
    #include <cstdio>
    #include <functional>
    #include <iostream>
    
    template <typename T>
    struct function_traits;
    
    //普通函数
    template <typename Ret, typename... Args>
    struct function_traits<Ret(Args...)> {
     public:
      // enum { arity = sizeof...(Args) };
      static const size_t arity = sizeof...(Args);
      typedef Ret function_type(Args...);
      // typedef Ret return_type;
      using return_type = Ret;
      using stl_function_type = std::function<function_type>;
      typedef Ret (*pointer)(Args...);
    
      template <size_t I>
      struct args {
        static_assert(I < arity,
                      "index is out of range, index must less than sizeof Args");
        using type = typename std::tuple_element<I, std::tuple<Args...>>::type;
      };
    };
    
    //函数指针
    template <typename Ret, typename... Args>
    struct function_traits<Ret (*)(Args...)> : function_traits<Ret(Args...)> {};
    
    // std::function
    template <typename Ret, typename... Args>
    struct function_traits<std::function<Ret(Args...)>>
        : function_traits<Ret(Args...)> {};
    
    // member function
    #define FUNCTION_TRAITS(...)                                             
      template <typename ReturnType, typename ClassType, typename... Args>   
      struct function_traits<ReturnType (ClassType::*)(Args...) __VA_ARGS__> 
          : function_traits<ReturnType(Args...)> {};
    
    FUNCTION_TRAITS()
    FUNCTION_TRAITS(const)
    FUNCTION_TRAITS(volatile)
    FUNCTION_TRAITS(const volatile)
    
    //函数对象
    template <typename Callable>
    struct function_traits : function_traits<decltype(&Callable::operator())> {};
    
    template <typename T>
    void PrintType() {
      std::cout << abi::__cxa_demangle(typeid(T).name(), nullptr, nullptr, nullptr)
                << std::endl;
    }
    int main(void) {
      int my_int = 10;
      std::cout << abi::__cxa_demangle(typeid(my_int).name(), nullptr, nullptr,
                                       nullptr)
                << std::endl;
    
      std::function<int(int)> f = [](int a) { return a; };
    
      //打印函数类型
      PrintType<function_traits<
          std::function<int(int)>>::function_type>();  //将输出int __cdecl(int)
    
      //打印函数的第一个参数类型
      PrintType<
          function_traits<std::function<int(int)>>::args<0>::type>();  //将输出int
    
      //打印函数的返回类型
      PrintType<function_traits<decltype(f)>::return_type>();  //将输出int
    
      //打印函数指针类型
      PrintType<function_traits<decltype(f)>::pointer>();  //将输出int
    
      int a = 2;
      int b = 3;
      auto lambda_add = [a, b](int c) -> int { return a + b + c; };
    
      auto my_add =
          new std::function<function_traits<decltype(lambda_add)>::return_type(
              function_traits<decltype(lambda_add)>::args<0>::type)>(lambda_add);
      int ret1 = (*my_add)(5);
      int ret2 = lambda_add(5);
      printf("ret %d %d 
    ", ret1, ret2);
    
      return 0;
    }
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  • 原文地址:https://www.cnblogs.com/zengjianrong/p/14364337.html
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