• 二叉搜索树(C++) 分类: C/C++ 数据结构与算法 2015-07-09 11:18 205人阅读 评论(0) 收藏


    #include <iostream>
    
    using namespace std;
    
    typedef struct BiTNode{
    	int data;
    	struct BiTNode *lchild, *rchild;
    }BiTNode,*BiTree;
    
    class solution{
    public:
    	bool searchBst(BiTree root, int key, BiTree f, BiTree *p)
    	{
    		if (!root)
    		{
    			*p = f;
    			return false;
    		}
    		else if (root->data == key)
    		{
    			*p = root;
    			return true;
    		}
    		else if (key < root->data)
    		{
    			searchBst(root->lchild, key, root, p);
    		}
    		else
    		{
    			searchBst(root->rchild, key, root, p);
    		}
    	}
    
    	bool insertNode(BiTree *root,int key)
    	{
    		BiTree p;
    		if (!searchBst(*root, key, NULL, &p))
    		{
    			BiTNode* s = new BiTNode;
    			s->data = key;
    			s->lchild = s->rchild = NULL;
    			if (!p)
    			{
    				*root = s;
    			}
    			else if (key < p->data)
    			{
    				p->lchild = s;
    			}
    			else
    			{
    				p->rchild = s;
    			}
    
    			return true;
    		}
    		else
    		{
    			return false;
    		}
    	}
    	
    	void printTree(BiTree root)
    	{
    		if (root == NULL)
    			return;
    		printTree(root->lchild);
    		cout << root->data << "  ";
    		printTree(root->rchild);
    	}
    
    	BiTNode* maxValue(BiTree root)
    	{
    		if (!root)
    			return NULL;
    		BiTNode* s = root;
    		while (s->rchild)
    		{
    			s = s->rchild;
    		}
    		return s;
    	}
    
    	BiTNode* minValue(BiTree root)
    	{
    		if (!root)
    			return NULL;
    		BiTNode* s = root;
    		while (s->lchild)
    		{
    			s = s->lchild;
    		}
    		return s;
    	}
    
    	bool Delete(BiTree* p)
    	{
    		BiTree q,s;	
    		if ((*p)->lchild == NULL)
    		{
    			BiTree q = *p;
    			*p = (*p)->rchild;
    			delete q;
    		}
    		else if ((*p)->rchild == NULL)
    		{
    			BiTree q = *p;
    			*p = (*p)->lchild;
    			delete q;
    		}
    		else
    		{
    			s = (*p)->lchild;
    			q = *p;
    			while (s->rchild)
    			{
    				q = s;
    				s = s->rchild;
    			}
    			(*p)->data = s->data;
    			if (*p == q)
    			{
    				q->lchild = s->lchild;
    			}
    			else
    			{
    				q->rchild = s->lchild;
    			}
    			delete s;
    		}
    		return true;	
    	}
    
    	bool DeleteBST(BiTree* root, int key)
    	{
    		if (!root && !(*root))
    			return false;
    		else
    		{
    			if (key == (*root)->data)
    				Delete(root);
    			else if (key < (*root)->data)
    				return DeleteBST(&((*root)->lchild), key);
    			else
    				return DeleteBST(&((*root)->rchild), key);
    		}		
    	}
    };
    
    int main()
    {
    	solution s;
    	BiTree root=NULL;
    	int a[10] = { 6, 4, 8, 5, 0, 9, 3, 7, 1, 2 };
    	for (int i = 0; i < 10; ++i)
    	{
    		s.insertNode(&root, a[i]);
    	}
    
    	cout << "前序遍历结果:" << endl;
    	s.printTree(root);
    	cout << endl;
    	cout << "最大值:" << endl;
    	cout << (s.maxValue(root))->data << endl;
    	cout << "最小值:" << endl;
    	cout << (s.minValue(root))->data << endl;
    	cout << "查找值为'3'的结点:" << endl;
    	BiTree p;
    	cout << (s.searchBst(root, 3, NULL, &p) ? "exist" : "no exist" )<< endl;
    	cout << (s.searchBst(root, 8, NULL, &p) ? "exist" : "no exist") << endl;
    	cout << (s.searchBst(root, 13, NULL, &p) ? "exist" : "no exist") << endl;
    	cout << "删除值为3的结点:" << endl;
    	s.DeleteBST(&root, 3);
    	s.printTree(root);
    	cout << endl;
    
    	return 0;
    }

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  • 原文地址:https://www.cnblogs.com/zclzqbx/p/4687066.html
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