题目链接:http://poj.org/problem?id=2451
题意:要搭建舞台举行晚会,公园里有很多长椅,每条长椅的位置由一条线段表示,椅子是固定的,搬不动。现在要求所有座位都能看到舞台,求舞台的最大面积是多少。
思路:先用半平面交求出凸变形,然后再根据差积求面积即可。
#include<bits/stdc++.h> #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<iostream> #include<algorithm> using namespace std; const int maxn=20010; const int bound=10000; const double esp= 1e-10; struct point { double x,y; }; struct node { point a,b; }; node pp[maxn]; int cnt,id[maxn],n; double at[maxn]; int q[maxn*2],front,rear,dg; point dpg[maxn]; void add(double x1,double y1,double x2,double y2) { pp[cnt].a.x =x1; pp[cnt].a .y =y1; pp[cnt].b.x =x2; pp[cnt++].b.y =y2; } void read() { scanf("%d",&n); cnt=0; double x1,x2,y1,y2; for(int i=0; i<n; i++) { scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2); add(x1,y1,x2,y2); } n+=4; add(0,0,bound,0); add(bound,0,bound,bound); add(bound,bound,0,bound); add(0,bound,0,0); } int is0(double a) { if(a<=esp&&a>=-esp) return 0; if(a>esp) return 1; return -1; } double det(double x1,double y1,double x2,double y2) { return x1*y2-x2*y1; } double ana(point p0,point p1,point p2) { return det(p1.x-p0.x,p1.y -p0.y,p2.x -p0.x,p2.y -p0.y ); } bool cmp(int a,int b) { if(at[a]<at[b]) return true; if(is0(at[a]-at[b])==0) if(is0(ana(pp[b].a,pp[b].b,pp[a].a ))>=0) return true; return false; } void deal() { for(int i=0; i<n; i++) { at[i]=atan2(pp[i].b.y-pp[i].a.y,pp[i].b.x -pp[i].a.x ); id[i]=i; } sort(id,id+n,cmp); int temp=1; for(int i=1; i<n; i++) if(is0(at[id[i-1]]-at[id[i]])!=0) id[temp++]=id[i]; n=temp; } point APP(node &t1,node &t2) { double d1,d2; point s1,e1,s2,e2; s1=t1.a ; e1=t1.b ; s2=t2.a ; e2=t2.b ; point temp; d1=ana(s2,e1,s1); d2=ana(e1,e2,s1); temp.x =(s2.x *d2+e2.x *d1)/(d2+d1); temp.y =(s2.y *d2+e2.y *d1)/(d2+d1); return temp; } bool judge(int x,int y,int now) { point temp=APP(pp[x],pp[y]); double d=ana(pp[now].a,pp[now].b,temp); if(is0(d)<0) return true; return false; } void solve() { int i; front=0; rear=1; q[0]=id[0]; q[1]=id[1]; for(i=2; i<n; i++) { while(front<rear&&judge(q[rear-1],q[rear],id[i])) rear--; while(front<rear&&judge(q[front],q[front+1],id[i])) front++; q[++rear]=id[i]; } while(front<rear&&judge(q[rear-1],q[rear],q[front])) rear--; while(front<rear&&judge(q[front],q[front+1],q[rear])) front++; q[++rear]=q[front]; dg=0; for(i=front+1; i<=rear; i++) dpg[dg++]=APP(pp[q[i-1]],pp[q[i]]); } double area() { double ans=0; for(int i=0; i<dg; i++) ans+=dpg[i].x*dpg[(i+1)%dg].y -dpg[(i+1)%dg].x *dpg[i].y ; ans=fabs(ans)/2.0; return ans; } int main() { read(); deal(); solve(); printf("%.1f ",area()); return 0; }