• Round #424 B. Keyboard Layouts


    There are two popular keyboard layouts in Berland, they differ only in letters positions. All the other keys are the same. In Berland they use alphabet with 26 letters which coincides with English alphabet.

    You are given two strings consisting of 26 distinct letters each: all keys of the first and the second layouts in the same order.

    You are also given some text consisting of small and capital English letters and digits. It is known that it was typed in the first layout, but the writer intended to type it in the second layout. Print the text if the same keys were pressed in the second layout.

    Since all keys but letters are the same in both layouts, the capitalization of the letters should remain the same, as well as all other characters.

    Input

    The first line contains a string of length 26 consisting of distinct lowercase English letters. This is the first layout.

    The second line contains a string of length 26 consisting of distinct lowercase English letters. This is the second layout.

    The third line contains a non-empty string s consisting of lowercase and uppercase English letters and digits. This is the text typed in the first layout. The length of s does not exceed 1000.

    Output

    Print the text if the same keys were pressed in the second layout.

    Examples
    input
    qwertyuiopasdfghjklzxcvbnm
    veamhjsgqocnrbfxdtwkylupzi
    TwccpQZAvb2017
    output
    HelloVKCup2017
    input
    mnbvcxzlkjhgfdsapoiuytrewq
    asdfghjklqwertyuiopzxcvbnm
    7abaCABAABAcaba7
    output
    7uduGUDUUDUgudu7
     1 #include <iostream>
     2 #include <stdio.h>
     3 #include <string.h>
     4 #include <algorithm>
     5 
     6 using namespace std;
     7 char s1[30],s2[30];
     8 int mp[256];
     9 char str[1005];
    10 int main(){
    11     scanf("%s%s",s1,s2);
    12     int len=strlen(s1);
    13     for(int i=0;i<len;i++)
    14         mp[s1[i]]=i;       //¼Ç¼λÖÃÐÅÏ¢
    15     scanf("%s",str);
    16     len=strlen(str);
    17     for (int i=0;i<len;i++){
    18         if(str[i]>='A'&&str[i]<='Z')
    19             printf("%c",toupper(s2[mp[tolower(str[i])]]));
    20         else if(str[i]>='a'&&str[i]<='z')
    21             printf("%c",s2[mp[str[i] ] ]);
    22         else  printf("%c",str[i]);
    23     }
    24     printf("
    ");
    25     return 0;
    26 }
     1 #include <bits/stdc++.h>
     2 using namespace std;
     3 int main(){
     4     map<char,char>mp;
     5     string s1,s2,c;
     6     cin>>s1>>s2>>c;
     7     for(int i=0;s2[i];i++)
     8         mp[s1[i]]=s2[i];
     9     for(int i=0;c[i];i++){
    10         char s;
    11         if(c[i]>='0'&&c[i]<='9')
    12             s=c[i];
    13         else if(c[i]>='a'&&c[i]<='z')
    14         s=mp[c[i]];
    15         else s=mp[c[i]+32]-32;
    16         cout<<s;
    17     }
    18     return 0;
    19 }
  • 相关阅读:
    【web安全】浅谈web安全之XSS
    【css】浅谈BFC
    nodejs笔记一--模块,全局process对象;
    逼真打字机效果;
    深入理解CSS3 animation的steps
    网址链接收藏
    用hoverclock插件实现HTML5时钟
    JS多种方法实现随机颜色;
    canvas实现跟随鼠标旋转的箭头
    封装insertAfter、addClass、格式化时间
  • 原文地址:https://www.cnblogs.com/z-712/p/7307947.html
Copyright © 2020-2023  润新知