codeforces B. The Same Calendar
The girl Taylor has a beautiful calendar for the year y. In the calendar all days are given with their days of week: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday.
The calendar is so beautiful that she wants to know what is the next year after y when the calendar will be exactly the same. Help Taylor to find that year.
Note that leap years has 366 days. The year is leap if it is divisible by 400 or it is divisible by 4, but not by 100 (https://en.wikipedia.org/wiki/Leap_year).
Input
The only line contains integer y (1000 ≤ y < 100'000) — the year of the calendar.
Output
Print the only integer y' — the next year after y when the calendar will be the same. Note that you should find the first year after y with the same calendar.
Examples
input
2016
output
2044
input
2000
output
2028
input
50501
output
50507
小析：求解出与给出年份完全相同的下一年，不仅需要平闰相同，还需要星期相同,
2018年12月1号 星期六
2019年12月1号 星期日
2020年12月1号 星期二（闰年）
1 def is_leap(year): 2 if (year % 400 == 0 or year % 4 == 0 and year % 100 != 0): 3 return 1 4 else: 5 return 0 6 7 8 if __name__ == '__main__': 9 year = 0 10 try: 11 year = int(input()) 12 except: 13 exit(0) 14 sum = 0 15 next_year = year + 1 16 while True: 17 if is_leap(next_year) == 0: 18 sum += 1 19 else: 20 sum += 2 21 if (sum % 7 == 0) and (is_leap(year) == is_leap(next_year)): 22 print(next_year) 23 break 24 else: 25 next_year += 1