【笔试】华为实习生 上机

Q1

input:A row of figures separated by commas

output:A row of figures separated by commas according to the original order.Each number=the original value*the nth time appeared

My answer：

#include<iostream>
#include<string>
#include<array>
#include<cmath>
using namespace std;


int main(){

    //输入获取 每个输入字符存入字符串inputString
    string inputString;
    cin>>inputString;
    int stringLen=inputString.length();
    
    //剔除逗号，逗号之间的数存入数组numArray的每个元素里
    int *numArray=new int[100]();
    int numArrayLen=0;
    
    int i=inputString.find(",");
    for(int j=0,jj=i-1;j<i,jj>=0;j++,jj--){
    numArray[0]+=(inputString[j]-48)*pow(10.0,jj);
    }

    inputString[i]=' ';
    int ii=inputString.find(",");
    
    while(ii!=string::npos){
        numArrayLen++;
    for(int j=i+1,jj=ii-i-2;j<ii,jj>=0;j++,jj--){
        numArray[numArrayLen]+=(inputString[j]-48)*pow(10.0,jj);
    }
    i=ii;
    inputString[ii]=' ';
    ii=inputString.find(",");
    }
    
    numArrayLen++;
    for(int j=i+1,jj=stringLen-i-2;j<stringLen,jj>=0;j++,jj--){
    numArray[numArrayLen]+=(inputString[j]-48)*pow(10.0,jj);
    }
    
    //计算每个数的出现次数,并更新数组
    int *numCount=new int[1000]();
    for(int j=0;j<=numArrayLen;j++){
        numCount[numArray[j]]++;
        numArray[j]*=numCount[numArray[j]];
    }

    //按照要求的格式输出
      for(int j=0;j<numArrayLen;j++)cout<<numArray[j]<<",";
      cout<<numArray[numArrayLen];
      
}

I did not realize my knowledge was so weak until the test.There are a lot of c++ function that I did not know before or didn't know how to use it well.Consequently,I must still keep fighting harder.By the way ,coding them strengthens my debug aility.F10~~

Ps:It is my first time to write something here in English.

On one hand ,to record a noob who hope to grow into a female geeker on programming.On the other hand,to train my English writing.

Please enlighten.