• 【题解】Luogu P1344 [USACO4.4]追查坏牛奶Pollutant Control


    原题传送门

    看到这种题,应该一眼就能知道考的是最小割

    没错这题就是如此简单,跑两遍最大流(最小割=最大流),一次边权为题目所给,一次边权为1

    还有一种优化,优化后只需跑一次最大流,把每条边的权值改成w*MOD+1(MOD为常数,珂以取八位质数233)

    答案为maxflow/MOD和maxflow%MOD

    基础版本

    #include <bits/stdc++.h>
    #define N 40
    #define M 2005
    #define inf 0x3f3f3f3f
    #define getchar nc
    using namespace std;
    inline char nc(){
        static char buf[100000],*p1=buf,*p2=buf;
        return p1==p2&&(p2=(p1=buf)+fread(buf,1,100000,stdin),p1==p2)?EOF:*p1++;
    }
    inline int read()
    {
        register int x=0,f=1;register char ch=getchar();
        while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
        while(ch>='0'&&ch<='9')x=(x<<3)+(x<<1)+ch-'0',ch=getchar();
        return x*f;
    }
    inline void write(register int x)
    {
        if(!x)putchar('0');if(x<0)x=-x,putchar('-');
        static int sta[20];register int tot=0;
        while(x)sta[tot++]=x%10,x/=10;
        while(tot)putchar(sta[--tot]+48);
    }
    inline int Min(register int a,register int b)
    {
        return a<b?a:b;
    }
    struct edge{
        int to,nxt,v;
    }e[M];
    int head[N],cnt=1;
    inline void add(register int u,register int v,register int w)
    {
        e[++cnt]=(edge){v,head[u],w};
        head[u]=cnt;
    }
    int n,m,s,t,maxflow=0;
    int cur[N],dep[N],gap[N];
    inline void bfs()
    {
        memset(dep,-1,sizeof(dep));
        memset(gap,0,sizeof(gap));
        dep[t]=0;
        ++gap[dep[t]];
        queue <int> q;
        q.push(t);
        while(!q.empty())
        {
            int u=q.front();
            q.pop();
            for(register int i=head[u];i;i=e[i].nxt)
            {
                int v=e[i].to;
                if(dep[v]!=-1)
                    continue;
                q.push(v);
                dep[v]=dep[u]+1;
                ++gap[dep[v]];
            }
        }
    }
    inline int dfs(register int u,register int flow)
    {
        if(u==t)
        {
            maxflow+=flow;
            return flow;
        }
        int used=0;
        for(register int i=cur[u];i;i=e[i].nxt)
        {
            cur[u]=i;
            int v=e[i].to;
            if(e[i].v&&dep[u]==dep[v]+1)
            {
                int tmp=dfs(v,Min(flow-used,e[i].v));
                if(tmp)
                    e[i].v-=tmp,e[i^1].v+=tmp,used+=tmp;
            }
            if(used==flow)
                return used;
        }
        --gap[dep[u]++]==0?dep[s]=n+1:++gap[dep[u]];
        return used;
    }
    inline void ISAP()
    {
        maxflow=0;
        bfs();
        while(dep[s]<=n)
        {
            memcpy(cur,head,sizeof(head));
            dfs(s,inf);
        }
    }
    int main()
    {
        n=read(),m=read();
        s=1,t=n;
        for(register int i=1;i<=m;++i)
        {
            int u=read(),v=read(),w=read();
            add(u,v,w),add(v,u,0);
        }
        ISAP();
        write(maxflow),putchar(' ');
        for(register int i=2;i<=cnt;++i)
            e[i].v=i%2?0:1;
        ISAP();
        write(maxflow);
        return 0;
    }
    

    优化版本

    #include <bits/stdc++.h>
    #define N 40
    #define M 2005
    #define inf 123456789123456789LL 
    #define ll long long 
    #define mod 19260817LL
    #define getchar nc
    using namespace std;
    inline char nc(){
        static char buf[100000],*p1=buf,*p2=buf;
        return p1==p2&&(p2=(p1=buf)+fread(buf,1,100000,stdin),p1==p2)?EOF:*p1++;
    }
    inline ll read()
    {
        register ll x=0,f=1;register char ch=getchar();
        while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
        while(ch>='0'&&ch<='9')x=(x<<3)+(x<<1)+ch-'0',ch=getchar();
        return x*f;
    }
    inline void write(register ll x)
    {
        if(!x)putchar('0');if(x<0)x=-x,putchar('-');
        static int sta[20];register int tot=0;
        while(x)sta[tot++]=x%10,x/=10;
        while(tot)putchar(sta[--tot]+48);
    }
    inline ll Min(register ll a,register ll b)
    {
        return a<b?a:b;
    }
    struct edge{
        int to,nxt;
        ll v;
    }e[M];
    int head[N],cnt=1;
    inline void add(register int u,register int v,register ll w)
    {
        e[++cnt]=(edge){v,head[u],w};
        head[u]=cnt;
    }
    int n,m,s,t;
    ll maxflow=0;
    int cur[N],dep[N],gap[N];
    inline void bfs()
    {
        memset(dep,-1,sizeof(dep));
        memset(gap,0,sizeof(gap));
        dep[t]=0;
        ++gap[dep[t]];
        queue <int> q;
        q.push(t);
        while(!q.empty())
        {
            int u=q.front();
            q.pop();
            for(register int i=head[u];i;i=e[i].nxt)
            {
                int v=e[i].to;
                if(dep[v]!=-1)
                    continue;
                q.push(v);
                dep[v]=dep[u]+1;
                ++gap[dep[v]];
            }
        }
    }
    inline ll dfs(register int u,register ll flow)
    {
        if(u==t)
        {
            maxflow+=flow;
            return flow;
        }
        ll used=0;
        for(register int i=cur[u];i;i=e[i].nxt)
        {
            cur[u]=i;
            int v=e[i].to;
            if(e[i].v&&dep[u]==dep[v]+1)
            {
                ll tmp=dfs(v,Min(flow-used,e[i].v));
                if(tmp)
                    e[i].v-=tmp,e[i^1].v+=tmp,used+=tmp;
            }
            if(used==flow)
                return used;
        }
        --gap[dep[u]++]==0?dep[s]=n+1:++gap[dep[u]];
        return used;
    }
    inline void ISAP()
    {
        maxflow=0;
        bfs();
        while(dep[s]<n)
        {
            memcpy(cur,head,sizeof(head));
            dfs(s,inf);
        }
    }
    int main()
    {
        n=read(),m=read();
        s=1,t=n;
        for(register int i=1;i<=m;++i)
        {
            int u=read(),v=read(),w=read();
            add(u,v,w*mod+1),add(v,u,0);
        }
        ISAP();
        write(maxflow/mod),putchar(' '),write(maxflow%mod);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/yzhang-rp-inf/p/10357244.html
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