• 树的判断(poj nyoj hduoj)


    题目:

    http://ac.jobdu.com/problem.php?pid=1481

    http://acm.nyist.net/JudgeOnline/problem.php?pid=129

    http://poj.org/problem?id=1308

    http://acm.hdu.edu.cn/showproblem.php?pid=1272

     题目意思就是判断一些给定的支点构成的树是不是一颗合法的树,

    判断是不是一颗合法的树如下:

            1、该树只有一个根节点

            2、不存在环

    对于上述两种情况采用如下进行判断:

            1、定义一个标识符,当这个点出现,并且父节点和自己相同的节点个数大于1,表示有多个根节点,反之不是

            2、在寻找父节点时,这两点指向同一个父节点,则出现了回路

     nyoj 和poj 直接使用下代码就ok ,hdu上面相应的改改(代码最后一个)一开始一直RE 后来看看了题目 是10^5,(纠结了)

    /*hdu 1272*/
    #include<stdio.h>
    #include <string.h>
    #define N 100005
    
    int f[N];
    int a[N];
    int flag = 1;
    int max = 0;
    
    void init()
    {
        memset(a,0,sizeof(a));
    
        memset(f,0,sizeof(f));
        max = 0;
        flag = 1;
        int i;
        for(i = 0; i <= N; i++)
            f[i] = i;
    }
    int find_f(int x)
    {
        if(x == f[x]) return x;
        else
        return f[x] = find_f(f[x]);
    }
    
    void add(int x,int y)
    {
        int fx = find_f(x);
        int fy = find_f(y);
        if(fx != fy)
            f[fy] = fx;
        else   flag = 0;
    }
    
    int main()
    {
        int  x,y;
        int fx,fy;
        init();
        while(1)
        {
            scanf("%d%d",&x,&y);
            if(x == -1 && y == -1) break;
            if(x ==0 && y == 0)
                {
                    int t = 0;
                    if(flag)
                      {
                          int i;
                          for(i = 0; i <= max; i++)
                            if(a[i] == 1)
                                {
                                    if(i == f[i]) t++;
                                }
                      }
                    if(t > 1)
                        flag = 0;
                    if(flag)
                     printf("Yes
    ");
                    else
                        printf("No
    ");
                   init();
                }
           else
            {
                if(flag)
                    {
                        max = max > (x > y ? x : y) ? max: (x > y ? x : y) ;
                        add(x,y);
                        a[x] = 1;
                        a[y] = 1;
                    }
            }
        }
        return 0;
    }
    
    /***
    判断是否有环,当他们的父相同则会出现环,然后是判断是否还有孤立的点(树存在)
    */
    #include<stdio.h>
    #include <string.h>
    #define N 10005
    
    int f[N];
    int a[N];
    int in[N];
    int flag = 1;
    int max = 0;
    
    void init()
    {
        memset(a,0,sizeof(a));
        memset(in,0,sizeof(in));
        memset(f,0,sizeof(f));
        max = 0;
        flag = 1;
        int i;
        for(i = 0; i <= N; i++)
            f[i] = i;
    }
    int find_f(int x)
    {
        if(x == f[x]) return x;
        else
        return find_f(f[x]);
    }
    int main()
    {
        int  x,y;
        int fx,fy;
        init();
        int tt = 0;
        while(1)
        {
            scanf("%d%d",&x,&y);
            if(x == -1 && y == -1)
                break;
            if(x == 0 && y == 0)
            {
                int t = 0,i;
                if(flag)
                {
                    for(i = 0; i <= max; i++)
                        if(a[i] == 1)
                        {
                            if(i == f[i]) t++;
                        }
                }
                if(t > 1)
                    flag = 0;
                tt++;
                if(flag)
                    printf("Case %d is a tree.
    ",tt);
                else
                    printf("Case %d is not a tree.
    ",tt);
    
                init();
            }
            else
            {
                a[x] = 1;
                a[y] = 1;
                in[y]++;
                max = max > (x > y ? x : y) ? max :  (x > y ? x : y);
                if(in[y] > 1)
                    {
                        flag = 0;
                    }
                if(flag == 1)
                {
                    fx = find_f(x);
                    fy = find_f(y);
                    //printf("%d  %d
    ",fx,fy);
                    if(fx != fy) f[fy] = fx;
                    else
                        flag = 0;
                }
    
            }
        }
        return 0;
    }
    

     最后跟新贴一个javaAC全部的代码

      1 import java.util.Scanner;
      2  
      3 //判断是否是树
      4  
      5 public class Main {
      6     private static My_Tree[] tree = new My_Tree[10007] ;//定义对象数组保存输入的值
      7     private static boolean Main_flag = false;
      8     private static int t = 1;
      9      
     10     public  static void init(){
     11         for(int i = 0; i < 10007; i++)
     12             tree[i] =new My_Tree(i,i,0,false);
     13         Main.Main_flag = false;
     14     }
     15     public static int find_f(int x){
     16         if(tree[x].getN() == tree[x].getF())
     17             return tree[x].getF();
     18         else
     19         return find_f(tree[x].getF());
     20     }
     21     public static void main(String[] args) {
     22         Scanner cin = new Scanner(System.in);
     23         int n,m;
     24         Main.init();
     25         while(true){
     26             n = cin.nextInt();
     27             m = cin.nextInt();
     28 //          System.out.println(Main.Main_flag);
     29             if(n == -1 && m == -1)
     30                     break;
     31             if(n == 0 && m == 0){
     32                 int t_tmp = 0;
     33                 if(!Main.Main_flag){
     34                     for(int i = 0; i < 10007; i++)
     35                         if(tree[i].isFlag()){
     36 //                          tree[i].print();
     37                             if(tree[i].getF() == tree[i].getN())
     38                                 t_tmp++;
     39                         }
     40                 }
     41                 if(t_tmp > 1)
     42                     Main.Main_flag = true;
     43                 if(!Main.Main_flag)
     44                     System.out.println("Case "+(Main.t++)+" is a tree.");
     45                 else
     46                     System.out.println("Case "+(Main.t++)+" is not a tree.");
     47                 Main.init();
     48             }
     49             else{
     50                 int fx,fy;
     51                  
     52                 tree[n].setFlag(true);
     53                 tree[m].setFlag(true);
     54                 tree[m].setIn(tree[m].getIn()+1);
     55                 if(tree[m].getIn() > 1)
     56                     Main.Main_flag = true;
     57                  
     58                 if(!Main.Main_flag){
     59                     fx = Main.find_f(n);
     60                     fy = Main.find_f(m);
     61                     if(fx != fy)
     62                         tree[m].setF(fx);
     63                     else
     64                         Main.Main_flag = true;
     65                 }
     66             }
     67         }
     68     }
     69  
     70 }
     71  
     72 class My_Tree{
     73     private int n,f,in;
     74     private boolean flag;
     75     public My_Tree(int n, int f, int in, boolean flag) {
     76         super();
     77         this.n = n;
     78         this.f = f;
     79         this.in = in;
     80         this.flag = flag;
     81     }
     82     public My_Tree() {
     83         super();
     84     }
     85      
     86     public int getN() {
     87         return n;
     88     }
     89     public void setN(int n) {
     90         this.n = n;
     91     }
     92     public int getF() {
     93         return f;
     94     }
     95     public void setF(int f) {
     96         this.f = f;
     97     }
     98     public int getIn() {
     99         return in;
    100     }
    101     public void setIn(int in) {
    102         this.in = in;
    103     }
    104     public boolean isFlag() {
    105         return flag;
    106     }
    107     public void setFlag(boolean flag) {
    108         this.flag = flag;
    109     }
    110     public void print(){
    111         System.out.println("--->"+n+f+in+flag);
    112     }
    113 }
    114 /**************************************************************
    115     Problem: 1481
    116     User: yangyin1217
    117     Language: Java
    118     Result: Accepted
    119     Time:790 ms
    120     Memory:105768 kb
    121 ****************************************************************/
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  • 原文地址:https://www.cnblogs.com/yyroom/p/3280557.html
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