Title:
Given an unsorted integer array, find the first missing positive integer.
For example,
Given [1,2,0]
return 3
,
and [3,4,-1,1]
return 2
.
Your algorithm should run in O(n) time and uses constant space.
思路:将元素放到合适的位置,例如1放到数组中0的位置,2放到1的位置...
class Solution { public: int firstMissingPositive(vector<int>& nums) { int n = nums.size(); for (int i = 0; i < n; ++i) { while (nums[i] > 0 && nums[i] <= n && nums[nums[i] - 1] != nums[i]) { swap(nums[i], nums[nums[i] - 1]); } } for (int i = 0; i < n; ++i) { if (nums[i] != i + 1) return i + 1; } return n + 1; } };