求连个多边形相交的面积
#include<bits/stdc++.h> using namespace std; const int maxn=555; const int maxisn=10; const double eps=1e-8; const double pi=acos(-1.0); int dcmp(double x){ if(x>eps) return 1; return x<-eps ? -1 : 0; } inline double Sqr(double x){ return x*x; } struct Point{ double x,y; Point(){x=y=0;} Point(double x,double y):x(x),y(y){}; friend Point operator + (const Point &a,const Point &b) { return Point(a.x+b.x,a.y+b.y); } friend Point operator - (const Point &a,const Point &b) { return Point(a.x-b.x,a.y-b.y); } friend bool operator == (const Point &a,const Point &b) { return dcmp(a.x-b.x)==0&&dcmp(a.y-b.y)==0; } friend Point operator * (const Point &a,const double &b) { return Point(a.x*b,a.y*b); } friend Point operator * (const double &a,const Point &b) { return Point(a*b.x,a*b.y); } friend Point operator / (const Point &a,const double &b) { return Point(a.x/b,a.y/b); } friend bool operator < (const Point &a, const Point &b) { return a.x < b.x || (a.x == b.x && a.y < b.y); } inline double dot(const Point &b)const{ return x*b.x+y*b.y; } inline double cross(const Point &b,const Point &c)const{ return (b.x-x)*(c.y-y)-(c.x-x)*(b.y-y); } }; Point LineCross(const Point &a,const Point &b,const Point &c,const Point &d){ double u=a.cross(b,c),v=b.cross(a,d); return Point((c.x*v+d.x*u)/(u+v),(c.y*v+d.y*u)/(u+v)); } double PolygonArea(Point p[],int n){ if(n<3) return 0.0; double s=p[0].y*(p[n-1].x-p[1].x); p[n]=p[0]; for(int i=1;i<n;i++){ s+=p[i].y*(p[i-1].x-p[i+1].x); } return fabs(s*0.5); } double CPIA(Point a[],Point b[],int na,int nb){ Point p[maxisn],temp[maxisn]; int i,j,tn,sflag,eflag; a[na]=a[0],b[nb]=b[0]; memcpy(p,b,sizeof(Point)*(nb+1)); for(i=0;i<na&&nb>2;++i){ sflag=dcmp(a[i].cross(a[i+1],p[0])); for(j=tn=0;j<nb;++j,sflag=eflag){ if(sflag>=0) temp[tn++]=p[j]; eflag=dcmp(a[i].cross(a[i+1],p[j+1])); if((sflag^eflag)==-2) temp[tn++]=LineCross(a[i],a[i+1],p[j],p[j+1]); } memcpy(p,temp,sizeof(Point)*tn); nb=tn,p[nb]=p[0]; } if(nb<3) return 0.0; return PolygonArea(p,nb); } double SPIA(Point a[],Point b[],int na,int nb){ int i,j; Point t1[4],t2[4]; double res=0.0,if_clock_t1,if_clock_t2; a[na]=t1[0]=a[0]; b[nb]=t2[0]=b[0]; for(i=2;i<na;i++){ t1[1]=a[i-1],t1[2]=a[i]; if_clock_t1=dcmp(t1[0].cross(t1[1],t1[2])); if(if_clock_t1<0) swap(t1[1],t1[2]); for(j=2;j<nb;j++){ t2[1]=b[j-1],t2[2]=b[j]; if_clock_t2=dcmp(t2[0].cross(t2[1],t2[2])); if(if_clock_t2<0) swap(t2[1],t2[2]); res+=CPIA(t1,t2,3,3)*if_clock_t1*if_clock_t2; } } return res;//面积交 //return PolygonArea(a,na)+PolygonArea(b,nb)-res;//面积并 } Point a[4],b[5]; int main() { double x1,x2,x3,x4,y1,y2,y3,y4; while(scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2)!=EOF) { scanf("%lf%lf%lf%lf",&x3,&y3,&x4,&y4); a[0]=Point(x1,y1); a[1]=Point(x2,y1); a[2]=Point(x1,y2); b[0]=Point(x3,y3); b[1]=Point(x3,y4); b[2]=Point(x4,y4); b[3]=Point(x4,y3); printf("%.8lf ",fabs(SPIA(a,b,3,4))); } }