• 普通链表的各种排序及常用操作


    声明

    • 内容根据数据结构、算法与应用C++描述书籍练习题的实现,实现普通链表的插入,选择,冒泡,计数排序(排列排序),交叉排序,奇偶交叉以及归并排序,链表的反转,循环元素移动,网上也有其他解答,由于新人刚学习算法。方法实现很笨,可能存在各种问题,网上这些方法很多,我只是记录一下自己的方法。DeBug的日常!!!
    • 书籍习题汇总
    • 数组描述排序

    前置条件

    template<class T>
    struct chainNode
    {
    	T element;
    	chainNode<T>* next;
    
    	chainNode() {}
    	chainNode(const T& element) { this->element = element; }
    	chainNode(const T& element, chainNode<T>* next)
    	{
    		this->element = element;
    		this->next = next;
    	}
    };
    
    //普通链表
    template<class T>
    class chain : public linearList<T>
    {
    public:
        ...
        void leftShift(int i);
        void reverse();
        void meld(chain<T>& a, chain<T>& b);
        void merge(chain<T>& a, chain<T>& b);
        void split(chain<T>& a, chain<T>& b);
        void insertSort();
        void bubbleSort();
        void selectSort();
        void countSort();
        ...
    protected:
    	chainNode<T>* firstNode;
    	int listSize;
    };
    
    //多调试,知其用
    

    插入排序

    template<class T>
    void chain<T>::insertSort()
    {
    	if (!firstNode || !firstNode->next)
    		return;
    	chainNode<T>* dummyNode = new chainNode<T>(INT_MIN);
    	chainNode<T>* prevNode, * currNode, * tempNode;
    	dummyNode->next = firstNode;
    	prevNode = firstNode;
    	currNode = firstNode->next;
    	while (currNode != nullptr)
    	{
    		if (currNode->element < prevNode->element)
    		{
    			tempNode = dummyNode;
    			while (tempNode->next->element < currNode->element)
    			{
    				tempNode = tempNode->next;
    			}
    			prevNode->next = currNode->next;
    			currNode->next = tempNode->next;;
    			tempNode->next = currNode;
    			currNode = prevNode->next;
    		}
    		else
    		{
    			prevNode = prevNode->next;
    			currNode = currNode->next;
    		}
    	}
    	firstNode = dummyNode->next;
    }
    

    冒泡排序

    template<class T>
    void chain<T>::bubbleSort()
    {
    	if (!firstNode || !firstNode->next)
    		return;
    	chainNode<T>* dummyNode, * prevNode, * currNode, * tailNode, * tempNode;
    	dummyNode = new chainNode<T>(-1, firstNode);
    	prevNode = dummyNode->next;
    	currNode = prevNode->next;
    	tailNode = firstNode->next;
    	while (tailNode != nullptr)
    		tailNode = tailNode->next;
    
    	while (prevNode->next != tailNode)
    	{
    		tempNode = dummyNode;
    		while (currNode != tailNode)
    		{
    			if (currNode->element < prevNode->element)
    			{
    				prevNode->next = currNode->next;
    				currNode->next = prevNode;
    				tempNode->next = currNode;
    				tempNode = tempNode->next;
    				currNode = prevNode->next;
    			}
    			else
    			{
    				prevNode = prevNode->next;
    				currNode = currNode->next;
    				tempNode = tempNode->next;
    			}
    		}
    		tailNode = prevNode;
    		prevNode = dummyNode->next;
    		currNode = prevNode->next;
    	}
    	firstNode = dummyNode->next;
    }
    

    选择排序

    template<class T>
    void chain<T>::selectSort()
    {
    	if (!firstNode || !firstNode->next)
    		return;
    	chainNode<T>* maxNode, * maxPrevNode;
    	chainNode<T>* currNode, * currPrevNode;
    	chainNode<T>* dummyNode, * tailNode;
    	dummyNode = maxPrevNode = currPrevNode = new chainNode<T>(INT_MIN, firstNode);
    	currNode = maxNode = firstNode;
    	tailNode = firstNode->next;
    	while (tailNode != nullptr)
    		tailNode = tailNode->next;;
    
    	while (maxNode->next != tailNode)
    	{
    		while (currNode->next != tailNode)
    		{
    			if (maxNode->element < currNode->element)
    			{
    				maxNode = currNode;
    				maxPrevNode = currPrevNode;
    			}
    			currNode = currNode->next;
    			currPrevNode = currPrevNode->next;
    		}
    		currPrevNode->next = maxNode;
    		maxPrevNode->next = currNode;
    		currNode->next = maxNode->next;
    		maxNode->next = tailNode;
    
    		//初始化尾节点和firstNode
    		tailNode = maxNode;
    		firstNode = dummyNode->next;
    
    		//初始化新一轮状态
    		maxNode = dummyNode->next;
    		currNode = maxNode->next;
    		maxPrevNode = dummyNode;
    		currPrevNode = maxPrevNode->next;
    	}
    }
    

    计数排序

    参考

    template<class T>
    void chain<T>::countSort()
    {
    	if (!firstNode || !firstNode->next)
    		return;
    	chainNode<T>* p, * pr;
    	chainNode<T>* dummyNode = new chainNode<T>(INT_MIN, firstNode);
    	p = firstNode->next;
    	int* r = new int[listSize];
    	for (int i = 0; i < listSize; ++i)
    		r[i] = 0;
    	int i = 1, j = 0;
    	while (p!=nullptr)
    	{
    		pr = dummyNode->next;
    		j = 0;
    		while (pr!=p)
    		{
    			if (pr->element <= p->element)
    				++r[i];
    			else
    				++r[j];
    			pr = pr->next;
    			++j;
    		}
    		p = p->next;
    		++i;
    	}
    
    	chainNode<T>* pb = dummyNode->next;
    	int k = 0, t;
    	T temp;
    	while (pb!=nullptr)
    	{
    		int i = 0;
    		chainNode<T>* pd = dummyNode->next;
    		while (k!=r[i])
    		{
    			pd = pd->next;
    			++i;
    		}
    		if (k != r[k])
    		{
    			temp = pb->element;
    			pb->element = pd->element;
    			pd->element = temp;
    			t = r[i];
    			r[i] = r[k];
    			r[k] = t;
    		}
    		pb = pb->next;
    		++k;
    	}
    	delete[] r;
    }
    

    交叉

    template<class T>
    void chain<T>::meld(chain<T>& a, chain<T>& b)
    {
    	a.checkIndex(a.size() - 1);
    	b.checkIndex(b.size() - 1);
    	int minIndex = std::min(a.size(), b.size());
    	int index = 0;
    	chainNode<T>* aNode;
    	chainNode<T>* bNode;
    	chainNode<T>* cNode;
    	chainNode<T>* tempNode;
    
    	firstNode = a.firstNode;
    	aNode = a.firstNode->next;
    	firstNode->next = b.firstNode;
    	bNode = b.firstNode->next;
    	cNode = firstNode->next;
    
    	for (; index < minIndex - 1; ++index)
    	{
    		cNode->next = aNode;
    		tempNode = aNode->next;
    		aNode->next = bNode;
    		aNode = tempNode;
    		cNode = bNode;
    		bNode = bNode->next;
    	}
    	if (a.size() > b.size())
    	{
    		while (aNode != nullptr)
    		{
    			cNode->next = aNode;
    			aNode = aNode->next;
    			cNode = cNode->next;
    		}
    	}
    	else if (a.size() < b.size())
    	{
    		while (bNode != nullptr)
    		{
    			cNode->next = bNode;
    			bNode = bNode->next;
    			cNode = cNode->next;
    		}
    	}
    	a.firstNode = nullptr;
    	b.firstNode = nullptr;
    	listSize = a.size() + b.size();
    }
    

    奇偶交叉

    template<class T>
    void chain<T>::split(chain<T>& a, chain<T>& b)
    {
    	chainNode<T>* aNode = nullptr;
    	chainNode<T>* bNode = nullptr;
    
    	while (firstNode != nullptr)
    	{
    		if (firstNode->element & 1)
    		{
    			if (a.size() == 0)
    			{
    				aNode = a.firstNode = firstNode;
    				firstNode = firstNode->next;
    				++a.listSize;
    				continue;
    			}
    			aNode->next = firstNode;
    			firstNode = firstNode->next;
    			aNode = aNode->next;
    			aNode->next = nullptr;
    			++a.listSize;
    		}
    		else
    		{
    			if (b.size() == 0)
    			{
    				bNode = b.firstNode = firstNode;
    				firstNode = firstNode->next;
    				++b.listSize;
    				continue;
    			}
    			bNode->next = firstNode;
    			firstNode = firstNode->next;
    			bNode = bNode->next;
    			bNode->next = nullptr;
    			++b.listSize;
    		}
    	}
    }
    

    归并

    template<class T>
    void chain<T>::merge(chain<T>& a, chain<T>& b)
    {
    	a.checkIndex(a.size() - 1);
    	b.checkIndex(b.size() - 1);
    
    	chainNode<T>* aNode = a.firstNode;
    	chainNode<T>* bNode = b.firstNode;
    	chainNode<T>* cNode = firstNode;
    
    	if (aNode->element <= bNode->element)
    	{
    		firstNode = cNode = aNode;
    		aNode = aNode->next;
    	}
    	else
    	{
    		firstNode = cNode = bNode;
    		bNode = bNode->next;
    	}
    
    	while (aNode != nullptr && bNode != nullptr)
    	{
    		if (aNode->element <= bNode->element)
    		{
    			cNode->next = aNode;
    			cNode = cNode->next;
    			aNode = aNode->next;
    		}
    		else
    		{
    			cNode->next = bNode;
    			cNode = cNode->next;
    			bNode = bNode->next;
    		}
    	}
    	if (aNode == nullptr)
    	{
    		while (bNode != nullptr)
    		{
    			cNode->next = bNode;
    			cNode = cNode->next;
    			bNode = bNode->next;
    		}
    	}
    	if (bNode == nullptr)
    	{
    		while (aNode != nullptr)
    		{
    			cNode->next = aNode;
    			cNode = cNode->next;
    			aNode = aNode->next;
    		}
    	}
    	a.firstNode = nullptr;
    	b.firstNode = nullptr;
    	listSize = a.size() + b.size();
    }
    

    反转

    template<class T>
    void chain<T>::reverse()
    {
    	if (listSize < 2)
    		return;
    	if (listSize == 2)
    	{
    		chainNode<T>* tempNode = firstNode;
    		firstNode = firstNode->next;
    		firstNode->next = tempNode;
    		tempNode->next = nullptr;
    		return;
    	}
    
    	chainNode<T>* preNode = firstNode;
    	firstNode = firstNode->next;
    	preNode->next = nullptr;
    	chainNode<T>* nextNode = firstNode->next;
    	for (int i = 0; i != listSize - 3; ++i)
    	{
    		firstNode->next = preNode;
    		preNode = firstNode;
    		firstNode = nextNode;
    		nextNode = firstNode->next;
    	}
    	firstNode->next = preNode;
    	nextNode->next = firstNode;
    	firstNode = nextNode;
    }
    

    循环元素移动

    template<class T>
    void chain<T>::leftShift(int number)
    {
    	chainNode<T>* deleteNode;
    	for (int i = 0; i < number; ++i)
    	{
    		deleteNode = firstNode;
    		firstNode = firstNode->next;
    		delete deleteNode;
    	}
    	listSize -= number;
    }
    
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  • 原文地址:https://www.cnblogs.com/ysjcqs/p/list.html
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