c++输入的高级操作

不等待回车直接输入一个字符

仅在Linux下有效

#include <termio.h>
int getcharl() {
	struct termios new_settings;
	struct termios stored_settings;
	tcgetattr(0,&stored_settings);
	new_settings = stored_settings;
	new_settings.c_lflag &= (~ICANON);
	new_settings.c_cc[VTIME] = 0;
	new_settings.c_cc[VMIN] = 1;
	tcsetattr(0, TCSANOW, &new_settings);
	int c = getchar();
	tcsetattr(0, TCSANOW, &stored_settings);
	return c;
}

输入不回显

仅在Linux下有效

#include <cstdlib>
system("stty -echo"); //输入不回显
system("stty echo"); // 输入回显

根据这个搞出来的迷惑操作

方向键控制

#include <cstdio>                     
#include <termio.h>
#include <cstdlib>
#include <queue>
#include <utility>
#include <ctime>
#define UP 65
#define LEFT 68
#define DOWN 66
#define RIGHT 67
using namespace std;
int getcharl() {
	struct termios new_settings;
	struct termios stored_settings;
	tcgetattr(0,&stored_settings);
	new_settings = stored_settings;
	new_settings.c_lflag &= (~ICANON);
	new_settings.c_cc[VTIME] = 0;
	new_settings.c_cc[VMIN] = 1;
	tcsetattr(0, TCSANOW, &new_settings);
	int c = getchar();
	tcsetattr(0, TCSANOW, &stored_settings);
	return c;
}
void gt(int x, int y) {
	printf("33[%d;%dH", x, y);
}
int main() {
	srand(time(0));
	printf("33c33[?25l");
	int x = 10, y = 10, lx, ly, len = 20;
	system("stty -echo");
	queue<pair<int, int> > q;
	int px = rand() % 27 + 1, py = rand() % 77 + 1;
	while(1) {
		gt(px, py), printf("33[32;7m 33[0m");
		while(q.size() > len) {
			gt(q.front().first, q.front().second);
			printf("  ");
			q.pop();
		}
		gt(x, y), printf("33[31;7m 33[0m");
		lx = x, ly = y;
		int c = getcharl();
		if (c == UP) x--;
		else if(c == DOWN) x++;
		else if(c == LEFT) y--;
		else if(c == RIGHT) y++;
		if (x < 1) x = 30;
		if (y < 1) y = 80;
		if (x > 30) x = 1;
		if (y > 80) y = 1;
		if (px == x && py == y) len+=10, px = rand() % 27 + 1, py = rand() % 77 + 1;
		q.push(make_pair(x,y));
		gt(lx, ly);
	}
	system("stty echo");
	return 0;
}