• springboot+oauth2.0异常重写处理(针对token失效)


    近来针对微服务框架开发,其中oauth2.0默认返回XML形式的token失效,不符合我们实际的开发需求,于是我参考网上一些博客重写了它,使其符合我们开发的需求。

    核心主要涉及两个类:

    import com.eqics.common.security.utils.ResultJsonUtil;
    import org.springframework.http.HttpStatus;
    import org.springframework.security.core.AuthenticationException;
    import org.springframework.security.oauth2.common.exceptions.InvalidTokenException;
    import org.springframework.security.web.AuthenticationEntryPoint;
    import org.springframework.stereotype.Component;
    import javax.servlet.ServletException;
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;
    import java.io.IOException;
    import java.util.HashMap;
    import java.util.Map;
    @Component
    public class AuthExceptionEntryPoint implements AuthenticationEntryPoint {
    
    
        @Override
        public void commence(HttpServletRequest request, HttpServletResponse response,
                             AuthenticationException authException) throws ServletException {
            Map<String, Object> map = new HashMap<String, Object>();
            Throwable cause = authException.getCause();
    
            response.setStatus(HttpStatus.OK.value());
            response.setHeader("Content-Type", "application/json;charset=UTF-8");
            try {
                if (cause instanceof InvalidTokenException) {
    
                    response.getWriter().write(ResultJsonUtil.build(
                            222222,
                            "token失效"
                    ));
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }
    

    ResourceServerConfig.java类中补充如下(找到主要方法):

    @Override
    public void configure(ResourceServerSecurityConfigurer resources) {
        resources.tokenServices(tokenServices());
        resources.authenticationEntryPoint(new AuthExceptionEntryPoint());
    
    }

    还有一个工具类ResultJsonUtil.java,内容如下:

    import java.util.List;
    import java.util.Map;
    public class ResultJsonUtil<T> {
    
        private int code;
        private int statusCode;
        private String msg;
        private T data;
    
        private static final int DEFAULT_STATUS_CODE = 0;
    
        /**
         * construction
         *
         * @param code       请求状态码
         * @param statusCode 信息状态码
         * @param msg        信息
         * @param data       数据
         */
        public ResultJsonUtil(int code, int statusCode, String msg, T data) {
            this.code = code;
            this.statusCode = statusCode;
            this.msg = msg;
            this.data = data;
        }
    
        public static String build(int code, int statusCode, String msg) {
            ResultJsonUtil<String> resultJsonUtil = new ResultJsonUtil<>(code, statusCode, msg, "");
            return resultJsonUtil.getResultJson();
        }
    
        public static String build(int code, String msg) {
            return ResultJsonUtil.build(code, ResultJsonUtil.DEFAULT_STATUS_CODE, msg);
        }
    
        public static String build(int code, int statusCode, String msg, JSONArray data) {
            ResultJsonUtil<JSONArray> resultJsonUtil = new ResultJsonUtil<>(code, statusCode, msg, data);
            return resultJsonUtil.getResultJson();
        }
    
        public static String build(int code, String msg, JSONArray data) {
            return ResultJsonUtil.build(code, ResultJsonUtil.DEFAULT_STATUS_CODE, msg, data);
        }
    
    
        public static String build(int code, int statusCode, String msg, Map data) {
            JSONObject jsonObjectData = JSONObject.parseObject(JSON.toJSONString(data));
            ResultJsonUtil<JSONObject> resultJsonUtil = new ResultJsonUtil<>(code, statusCode, msg, jsonObjectData);
            return resultJsonUtil.getResultJson();
        }
    
        public static String build(int code, String msg, Map data) {
            return ResultJsonUtil.build(code, ResultJsonUtil.DEFAULT_STATUS_CODE, msg, data);
        }
    
    
        public static String build(int code, int statusCode, String msg, List data) {
            JSONArray jsonArrayData = JSONArray.parseArray(JSON.toJSONString(data));
            return ResultJsonUtil.build(code, statusCode, msg, jsonArrayData);
        }
    
        public static String build(int code, String msg, List data) {
            return ResultJsonUtil.build(code, ResultJsonUtil.DEFAULT_STATUS_CODE, msg, data);
        }
    
        private String getResultJson() {
            JSONObject jsonObject = new JSONObject();
            jsonObject.put("code", this.code);
            jsonObject.put("msg", this.msg);
            return JSON.toJSONString(jsonObject, SerializerFeature.DisableCircularReferenceDetect);
        }
    }

    本文主要参考了这篇文章:
    Spring Cloud:Security OAuth2 自定义异常响应

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  • 原文地址:https://www.cnblogs.com/youcong/p/13548726.html
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