两道简单的机试题目

两道简单的机试题目  1.统计一个英语句子中最大单词的长度   2.统计一个字符串内大写字母，空格以及数字的个数

    class Program
    {       
        static void Main(string[] args)
        {
            CountLength();
            CountNum();
            Console.Read();
        }
        //统计一个英语句子中最大单词的长度
        private static void CountLength()
        {
            string test = "I am a good man";
            string[] arr = test.Split(' ');
            int max = 0;
            foreach (string str in arr)
            {
                int len = str.Length;
                if (len > max)
                {
                    max = len;
                }
            }
            Console.WriteLine(max);//结果正确：4          
        }
        //统计一个字符串内大写字母，空格以及数字的个数

        解法一：
        private static void CountNum()
        {
            string test = "Avs  fdfdKLJL 3232 dsdss323232LOJO";
            int numUpper = 0, numSpace = 0, numNumber = 0;
            foreach (char ch in test)
            {
                if (ch >= 'A' && ch <= 'Z')
                {
                    numUpper++;
                }
                if (ch >= '0' && ch <= '9')
                {
                    numNumber++;
                }
                if (ch == ' ')
                {
                    numSpace++;
                }
            }
            Console.WriteLine("大写字母数量：" + numUpper + "数字数量：" + numNumber + "空格数量:" + numSpace);
        }
    }

    解法二：使用正则表达式

            Regex rx = new Regex(@"[A-Z]");
            string str = "Avs  fdfdKLJL 3232 dsdss323232LOJO";
            int count = rx.Matches(str).Count;
            MatchCollection mc = rx.Matches(str);
            Console.WriteLine(mc.Count);
            Console.WriteLine(count);

            rx = new Regex(@"[d]");
            count = rx.Matches(str).Count;
            Console.WriteLine(count);

            rx = new Regex(@"[s]");
            count = rx.Matches(str).Count;
            Console.WriteLine(count);

            Console.ReadKey();