Codeforces Round #411 A. Fake NP

A. Fake NP

time limit per test  

1 second

memory limit per test  

256 megabytes

 

Tavak and Seyyed are good friends. Seyyed is very funny and he told Tavak to solve the following problem instead of longest-path.

You are given l and r. For all integers from l to r, inclusive, we wrote down all of their integer divisors except 1. Find the integer that we wrote down the maximum number of times.

Solve the problem to show that it's not a NP problem.

Input

The first line contains two integers l and r (2 ≤ l ≤ r ≤ 109).

Output

Print single integer, the integer that appears maximum number of times in the divisors.

If there are multiple answers, print any of them.

 

input

19 29

output

2

input

3 6

output

3

Note:

The first example: from 19 to 29 these numbers are divisible by 2: {20, 22, 24, 26, 28}.

The second example: from 3 to 6 these numbers are divisible by 3: {3, 6}.

题目大意：

　　　　　给定一个范围，输出一个整数x，（使得这个范围内能整除x的整数个数最多）

解题思路：

　　　　　刚开始写的时候没想辣么多，处理超级复杂，之后仔细想想其实只有两种情况

　　　　　1、当l和r相同时任意输出一个。  2、当l和r不同时输出2（所有的偶数都能被2整除）

AC代码：

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
#include <algorithm>
using namespace std;

int main ()
{
    int l,r;
    while (~scanf("%d %d",&l,&r))
    {
        if (l == r)
            printf("%d
",l);
        else
            printf("2
");
    }
    return 0;
}