java:利用xpath删除xml中的空节点

原始xml内容：

<data>
  <a> </a>
  <b>b1</b>
  <awb>
    <awbpre>123</awbpre>
    <awbno></awbno>
  </awb>
  <spls>
    <spl />
  </spls>
</data>

可用下面的代码去掉 <awbno></awbno>、<spls><spl/></spls>这二个空节点 （注<a> </a>中间有一个空格，不算空节点）

    @Test
    public void testDeleteEmptyNode() throws DocumentException {
        String xmlOrigin = "<data><a> </a><b>b1</b><awb><awbpre>123</awbpre><awbno></awbno></awb><spls><spl/></spls></data>";
        SAXReader saxReader = new SAXReader();
        Document document = saxReader.read(new ByteArrayInputStream(xmlOrigin
                .getBytes()));

        while (true) {
            @SuppressWarnings("unchecked")
            List<Element> list = document.selectNodes("//*[not(node())]");
            if (list == null || list.size() <= 0) {
                break;
            }
            for (Element e : list) {
                System.out.println(e.getName());
                e.getParent().remove(e);
            }
        }
        System.out.println(document.asXML());

    }

以上代码使用了dom4j

输出内容：

awbno
spl
spls
<?xml version="1.0" encoding="UTF-8"?>
<data><a> </a><b>b1</b><awb><awbpre>123</awbpre></awb></data>

即：

<data>
  <a> </a>
  <b>b1</b>
  <awb>
    <awbpre>123</awbpre>
  </awb>
</data>