发现区间按左端点排序后右端点也是单调的,所以扫一遍就行了,用权值线段树维护第(k)大
#include<algorithm>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<map>
#define int long long
#define lc (p<<1)
#define rc (p<<1|1)
using namespace std;
const int MAXN=2000010;
const int MAXM=500010;
inline int read(){
int x=0,f=1; char c=getchar();
while(c<'0'){ if(c=='-') f=-1; c=getchar(); }
while(c>='0') x=x*10+c-'0',c=getchar();
return x*f;
}
int n,m,a[MAXN],t[MAXN],cnt,num;
struct Query{
int l,r,k,id;
} q[MAXM];
inline bool cmp(Query x,Query y){
return x.l<y.l;
}
map<int,int> Map;
int rev[MAXN];
int tree[MAXN];
inline void update(int k,int d,int p=1,int l=1,int r=num){
if(l==r){
tree[p]+=d;
return;
}
int mid=(l+r)>>1;
if(k<=mid) update(k,d,lc,l,mid);
else update(k,d,rc,mid+1,r);
tree[p]=tree[lc]+tree[rc];
}
inline int query(int k,int p=1,int l=1,int r=num){
if(l==r) return l;
int mid=(l+r)>>1;
if(tree[lc]>=k) return query(k,lc,l,mid);
else return query(k-tree[lc],rc,mid+1,r);
}
int ans[MAXN];
signed main(){
n=read(); m=read();
for(int i=1;i<=n;++i)
a[i]=read(),t[++cnt]=a[i];
for(int i=1;i<=m;++i)
q[i].l=read(),q[i].r=read(),q[i].k=read(),q[i].id=i;
sort(q+1,q+1+m,cmp);
sort(t+1,t+1+cnt);
t[0]=t[1]-1;
for(int i=1;i<=cnt;++i)
if(t[i]!=t[i-1]) Map[t[i]]=++num,rev[num]=t[i];
int L=1,R=0;
for(int i=1;i<=m;++i){
while(R<q[i].r) update(Map[a[++R]],1);
while(L<q[i].l) update(Map[a[L++]],-1);
ans[q[i].id]=rev[query(q[i].k)];
}
for(int i=1;i<=m;++i)
printf("%lld
",ans[i]);
return 0;
}