离散化,线段树维护区间修改,发现询问都是单点的(max),不妨把标记留在点上,不用下传,查询时取个(max)就可以了
#include<algorithm>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<map>
#define lc (p<<1)
#define rc (p<<1|1)
using namespace std;
const int MAXN=400010;
const int MAXM=1600010;
inline int read(){
int x=0,f=1; char c=getchar();
while(c<'0'){ if(c=='-') f=-1; c=getchar(); }
while(c>='0') x=x*10+c-'0',c=getchar();
return x*f;
}
int n,x[MAXN],cnt,num;
struct Data{
int l,r,h;
} a[MAXN];
map<int,int> Map;
int tree[MAXM],rev[MAXN];
inline void update(int L,int R,int h,int p=1,int l=1,int r=num){
if(L<=l&&r<=R){
tree[p]=max(tree[p],h);
return;
}
int mid=(l+r)>>1;
if(L<=mid) update(L,R,h,lc,l,mid);
if(R>mid) update(L,R,h,rc,mid+1,r);
}
inline int query(int x,int p=1,int l=1,int r=num){
if(l==r) return tree[p];
int mid=(l+r)>>1,ans=tree[p];
if(x<=mid) ans=max(ans,query(x,lc,l,mid));
else ans=max(ans,query(x,rc,mid+1,r));
return ans;
}
inline bool cmp(Data x,Data y){
if(x.l!=y.l)
return x.l<y.l;
return x.r<y.r;
}
int ansx[MAXN],ansy[MAXN],ansnum;
int main(){
n=read();
for(int i=1;i<=n;++i)
a[i].h=read(),a[i].l=read(),a[i].r=read(),--a[i].r;
sort(a+1,a+1+n,cmp);
for(int i=1;i<=n;++i){
x[++cnt]=a[i].l;
x[++cnt]=a[i].l+1;
x[++cnt]=a[i].r;
x[++cnt]=a[i].r+1;
}
x[0]=x[1]-1;
sort(x+1,x+1+cnt);
for(int i=1;i<=cnt;++i)
if(x[i]!=x[i-1]) Map[x[i]]=++num,rev[num]=x[i];
++num;
for(int i=1;i<=n;++i)
update(Map[a[i].l],Map[a[i].r],a[i].h);
int last=0;
for(int i=1;i<=num;++i){
int tmp=query(i);
if(tmp!=last){
if(tmp>last){
ansx[++ansnum]=rev[i],ansy[ansnum]=last;
ansx[++ansnum]=rev[i],ansy[ansnum]=tmp;
}
else{
ansx[++ansnum]=rev[i-1]+1,ansy[ansnum]=last;
ansx[++ansnum]=rev[i-1]+1,ansy[ansnum]=tmp;
}
last=tmp;
}
}
printf("%d
",ansnum);
for(int i=1;i<=ansnum;++i)
printf("%d %d
",ansx[i],ansy[i]);
return 0;
}